Answer:
A
Step-by-step explanation:
Answer:
0
Step-by-step explanation:
Thinking process:
= 
by Stoke's Theorem
= 
since z = 
<h3>
Answer: Choice A</h3>
Domain = (a,b]
Range = [mc + n,md + n)
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Explanation:
The domain stays the same because we still have to go through f(x) as our first hurdle in order to get g(x).
Think of it like having 2 doors. The first door is f(x) and the second is g(x). The fact g(x) is dependent on f(x) means that whatever input restrictions are on f, also apply on g as well. So going back to the "2 doors" example, we could have a problem like trying to move a piece of furniture through them and we'd have to be concerned about the f(x) door.
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The range will be different however. The smallest value in the range of f(x) is y = c as it is the left endpoint. So the smallest f(x) can be is c. This means the smallest g(x) can be is...
g(x) = m*f(x) + n
g(x) = m*c + n
All we're doing is replacing f with c.
So that means mc+n is the starting point of the range for g(x).
The ending point of the range is md+n for similar reasons. Instead of 'c', we're dealing with 'd' this time. The curved parenthesis says we don't actually include this value in the range. A square bracket means include that value.
The <em><u>correct answer</u></em> is:
AAS
Explanation:
AAS stands for "angle-angle-side." This states that if two angles and a non-included side of one triangle are congruent to the corresponding two angles and non-included side of another triangle, then the triangles are congruent.
In these triangles, we have ∠CAB ≅ ∠CDB given to us to begin with. Throughout the proof, we find that ∠ABC ≅ ∠DCB. We also have that CB is congruent to itself. This is two angles and a side not included, so this is AAS.
