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astraxan [27]
3 years ago
10

A(4, -1), B(3, 8), C(-1, 1); y = -2

Mathematics
1 answer:
nevsk [136]3 years ago
6 0

Answer:

Point A: (4, -3)

Point B: (3, -12)

Point C: (-1, -5)

Step-by-step explanation:

Reflection of point A:

The x will stay the same and only the y will change.

Take the y-coordinate and subtract it from the reflection line while getting the absolute value..

|(-1) - (-2)| = |1| = 1

This means, point A is one unit down the line y = -2

(-2) - 1 = -3

The coordinate for A will now be (4, -3).

Reflection of point B:

Again, the x will stay the same and only the y will change.

Using the absolute value, get the y-coordinate and subtract it from the reflection line again..

|(8) - (-2)| = |10| = 10

This means, point A is five unit down the line y = -2

(-2) - 10 = -17

The coordinate for B will now be (3, -12).

Reflection of point C:

I think you get the gist of it.

|(1) - (-2)| = |3| = 3

(-2) - 3 = -5

The coordinate for C will now be (-1, -5).

I added an image down below of what the reflection looks like. Sometimes it helps to see things visually.

The red triangle is the original image and the blue triangle is the image after the reflection. The purple line is the reflection line y = -2

Hope this helped!

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a) 0.2578 = 25.78% probability that the amount of collagen is greater than 60 grams per mililiter.

b) 0.9994 = 99.94% the probability that the amount of collagen is less than 90 grams per mililiter.

c) 68.26% of compounds formed from the extract of this plant fall within 1 standard deviation of the mean

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The collagen amount was found to be normally distributed with a mean of 65 and standard deviation of 7.7 grams per mililiter.

This means that \mu = 65, \sigma = 7.7

a. What is the probability that the amount of collagen is greater than 60 grams per.

This is 1 subtracted by the pvalue of Z when X = 60. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 65}{7.7}

Z = -0.65

Z = -0.65 has a pvalue of 0.2578

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b. What is the probability that the amount of collagen is less than 90 grams per.

This is the pvalue of Z when X = 90.

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 65}{7.7}

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Z = 3.25 has a pvalue of 0.9994

0.9994 = 99.94% the probability that the amount of collagen is less than 90 grams per mililiter.

c. What percentage of compounds formed from the extract of this plant fall within 1 standard deviation of the mean?

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Z = 1 has a pvalue of 0.8413

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