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4vir4ik [10]
3 years ago
14

THIS IS FOR 27 POINTS!!! EXPLAIN PLEASE!!!! Solve -9(2+a) + 4(2a+9)=11

Mathematics
2 answers:
Sindrei [870]3 years ago
8 0
So,

First you have to distribute the numbers outside of the parentheses (you multiply them with the numbers inside of the parentheses

-18+(-9a) + 8a +36=11
Then collect like terms
18-1a =11
 -18    -18
---------------------
-1a=-7
Divide both sides by -1
a=7




Verdich [7]3 years ago
3 0
-9(2+a) + 4(2a+9)=11\\ -18-9a+8a+36=11\\ -a=-7\\ a=7
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lidiya [134]

Answer:

f(-2) = 0

f(1) = 12

f(2) = 5

Step-by-step explanation:

f(-2) will lie in the function f(x) =x^2 - 4

\therefore f( - 2) =  {( - 2)}^{2}  - 4 = 4 - 4 = 0

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Given that A and B are true and X and Y are false, determine the truth value of the following proposition: ~[(A ⊃ Y) v ~(X ⊃ B)]
Anni [7]

Answer:

The value of the proposition is FALSE

Step-by-step explanation:

~[(A ⊃ Y) v ~(X ⊃ B)] ⋅ [~(A ≡ ~X) v (B ⊃ X)]

Let's start with the smallest part: ~X. The symbol ~ is negation when X is true with the negation is false and vice-versa. In this case, ~X is true (T)

~[(A ⊃ Y) v ~(X ⊃ B)] ⋅ [~(A ≡ T) v (B ⊃ X)]

Now the parts inside parenthesis:  (A ⊃ Y),(X ⊃ B),(A ≡ T) and (B ⊃ X). The symbol ⊃ is the conditional and A ⊃ Y is false when Y is false and A is true, in any other case is true. The symbol ≡ is the biconditional and A ≡ Y is true when both A and Y are true or when both are false.

(A ⊃ Y) is False (F)

(X ⊃ B) is True (T)

(A ≡ T) is True (T)

(B ⊃ X) is False (F)

~[(F) v ~(T)] ⋅ [~(T) v (F)]

The two negations inside the brackets must be taken into account:

~[(F) v F] ⋅ [F v (F)]

The symbol left inside the brackets v is the disjunction, and A v Y is false only  with both are false. F v (F) is False.

~[F] ⋅ [F]

Again considerating the negation:

T⋅ [F]

Finally, the symbol ⋅ is the conjunction, and A v Y is true only with both are true.

T⋅ [F] is False.

5 0
3 years ago
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