f(3x - 1) = 6x - 1
Rewrite 6x - 1 as a function of 3x - 1:
6x - 1 = 6x - 2 + 1 = 2(3x - 1) + 1
That is,
f(3x - 1) = 2(3x - 1) + 1
which means
f(x) = 2x + 1
and so
f(0) = 2*0 + 1 = 1
i would pick number C) since i think it would be the correct answer
Answer:
73.5
Step-by-step explanation:
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Answer:
23
Step-by-step explanation:
Its half of TU(46).
Hope it helps!