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3 years ago

9

A rectangle's perimeter and area have the same value. The width of the rectangle is 6 units. What is the length of the rectangle

in units?

1 answer:

Sliva [168]3 years ago

8 0

Answer:

The length ot rectangle is 3 units.

Step-by-step explanation:

The formula for perimeter is P = 2l + 2w and the area is A = l×w. Assuming that the perimeter and area have the same values so you have to compare it :

$perimeter = 2l + 2w$

$area= l \times w$

$perimeter = area$

$2l + 2w = lw$

$let \: w = 6$

$2l + 2(6) = 6l$

$2l + 12 = 6l$

$12 = 6l - 2l$

$4l = 12$

$l = 3 \: units$

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Oduvanchick [21]

Answer: 48 kilogramos de fruta

Step-by-step explanation:

Hola, para resolver este problema simplemente hay que sumar las cantidades de cada fruta:

Kilos de manzanas + kilos de mangos+ kilos de naranjas:

Matemáticamente hablando:

34+12+2 = 48 kg

Elena compro 48 kilogramos de fruta en total.

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4 years ago

Right triangles abc and dbc with right angle c are given below. If cos(a)=15,ab=12 and cd=2, find the length of bd.

dmitriy555 [2]

see the attached figure to better understand the problem

we have that

$cos(A)=\frac{1}{5} \\ AB=12\ units\\ CD=2\ units$

Step 1

<u>Find the value of AC</u>

we know that

in the right triangle ABC

$cos (A)=(AC/AB)\\AC=AB*cos(A)$

substitute the values in the formula

$AC=12*(1/5)\\ AC=2.4\ units$

Step 2

<u>Find the value of BC</u>

we know that

in the right triangle ABC

Applying the Pythagorean Theorem

$AB^{2} =AC^{2}+BC^{2}\\ BC^{2}=AB^{2} -AC^{2}$

substitute the values

$BC^{2}=12^{2} -2.4^{2}\\BC^{2}= 138.24\\ BC=11.76\ units$

Step 3

<u>Find the value of BD</u>

we know that

in the right triangle BCD

Applying the Pythagorean Theorem

$BD^{2} =DC^{2}+BC^{2}$

substitute the values

$BD^{2} =2^{2}+11.76^{2}$

$BD=11.93\ units$

therefore

<u>the answer is</u>

the length of BD is 11.93 units

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3 years ago

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I'm confused when I did it I got .35 and you divide
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4 years ago

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Marina86 [1]

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3 years ago

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In a game of poker a hand of five cards is dealt to each player from a deck of 52 cards. find the probablility of a hand contain

aalyn [17]

Answer:

0.00597

Step-by-step explanation:

Given,

Total number of cards = 52,

In which flush cards = 20,

Also, the number of spade flush cards = 5,

Since,

$\text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}$

Thus, the probability of a hand containing a spade flush, if each player has 5 cards

$=\frac{\text{Ways of selecting a spade flush card}}{\text{Total ways of selecting five cards}}$

$=\frac{^{20}C_5}{^{52}C_5}$

$=\frac{\frac{20!}{5!15!}}{\frac{52!}{5!47!}}$

$=\frac{15504}{2598960}$

= 0.00597

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3 years ago