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2 years ago

Which answer describes the type of sequence?

Mathematics

2 answers:

Stels [109]2 years ago

7 0

Answer:

Neither arithmetic nor geometric.

Step-by-step explanation:

3241004551 [841]2 years ago

4 0

Answer:

3. neither

Step-by-step explanation:

There is no common difference:

-88 - -99 = 11 and -66 - -88 = 22

Also no common ratio:

-88/99 is not equal to -66/-88.

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Two points on the line are (0, 4) and (7, 18). Use the points to first determine the slope and y-intercept. Then write the equat

Nadya [2.5K]

9514 1404 393

Answer:

a. m = 2; y intercept = (0, 4); y = 2 x + 4

Step-by-step explanation:

The slope can be found using the formula ...

m = (y2 -y1)/(x2 -x1)

m = (18 -4)/(7 -0) = 14/7

m = 2

The y-intercept is the first given point: (0, 4).

The equation for the line in slope-intercept form is

y = mx + b

Here, we have m=2 and b=4, so the equation is ...

y = 2x +4

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2 years ago

Which equation represents the graph?

klio [65]

The second option.

That is because
$y -3 = - \frac{1}{2}(x + 1) \\ (y -3)+3 = (- \frac{1}{2} x - \frac{1}{2}) + 3 \\ y = - \frac{1}{2}x + 2 \frac{1}{2}$

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3 years ago

A total star eclipse occurs when the moon passed between the sun and the earth causing the sky to go dark. The length of darknes

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2 minutes and 23 seconds

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3 years ago

Suppose x is a real number and epsilon > 0. Prove that (x - epsilon, x epsilon) is a neighborhood of each of its members; in

kaheart [24]

Answer:

See proof below

Step-by-step explanation:

We will use properties of inequalities during the proof.

Let $y\in (x-\epsilon,x+\epsilon)$ . then we have that $x-\epsilon$ . Hence, it makes sense to define the positive number delta as $\delta=\min\{x+\epsilon-y,y-(x-\epsilon)\}$ (the inequality guarantees that these numbers are positive).

Intuitively, delta is the shortest distance from y to the endpoints of the interval. Now, we claim that $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ , and if we prove this, we are done. To prove it, let $z\in (y-\delta,y+\delta)$ , then $y-\delta$ . First, $\delta \leq y-(x-\epsilon)$ then $-\delta \geq -y+x-\epsilon$ hence $z>y-\delta \geq x-\epsilon$

On the other hand, $\delta \leq x+\epsilon-y$ then $z$ hence $z$ . Combining the inequalities, we have that $x-\epsilon$ , therefore $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ as required.

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3 years ago

Suppose y varies directly with x. If y = 6 when x = -2, find x when y = 15.

s2008m [1.1K]

D because u going to take y6 and y 15 multiples the number it equal to y90 and take x-2 divide into 90

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2 years ago

Read 2 more answers