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Finger [1]
3 years ago
7

QUESTION 2.1 POINT

Mathematics
1 answer:
oee [108]3 years ago
8 0

Answer: 99.56%

Step-by-step explanation:

Well assuming we're working with a full poll of all 100% of students, and only 0.44%, so 100 - .44 is 99.56

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Question 2 (5 points)
Anuta_ua [19.1K]

Answer:

The greatest common factor is 8xyz

Step-by-step explanation:

To find the greatest common factor of an expression involving numbers and variables, we find each greatest common factor separately.

Numbers:

48, 24 and 56.

We find the greatest common factor factoring them simultaneously while all can be factored by the same number. The GCF is the multiplication of the factors. So

48 - 24 - 56|2

24 - 12 - 28|2

12 - 6 - 14|2

6 - 3 - 7|

They cant be factored by the same factors anymore, so the numeric GCF is 8.

Variables:

For each variable, the GCF will be the lowest exponent.

Variable x: We have exponents 1, 2 and 2. So the GCF is x^1 = x

Variable y: We have exponents 3, 3 and 1. So the GCF is y^1 = y

Variable z: We have exponents 1, 1 and 1. So the GCF is z^1 = z

The greatest common factor is:

8*x*y*z = 8xyz

4 0
3 years ago
Find the surface area of the cylinder in terms of T. 9 cm 19 cm Not drawn to scale O 211.5 cm 2 0 382.57 cm 2. O 333 77 cm2 o 50
Svetllana [295]

Answer:

hey the answer is cylinder= 211.5л!

5 0
3 years ago
Min read 1/8 of his book before lunch and 1/4 of his book after lunch. He says he has read 2/12 ​of his book.
Zigmanuir [339]

Answer:

neither

Step-by-step explanation:

he has read 3/6 of his book

4 0
3 years ago
Can anyone help me with this please!!? I’ll mark you brainliest!!
djverab [1.8K]

Answer:

each square is 5". the base is 4x4 squares- so 20 inches square. 20x20= 400sq inches.

the semicircle at the top is 20 inches in diameter, which makes the radius 10 inches.

pi× 10^2= 314.16.

duvide that by 2 to get a semicircle- 157.8

so, the total area is the 400+ 157.8, for a total area of 557.8 square inches

3 0
3 years ago
Segment AB has length a and is divided by points P and Q into AP , PQ , and QB , such that AP = 2PQ = 2QB. A) Find the distance
Deffense [45]

Answer:

A) \frac{7}{8}a

B) \frac{5}{8}a

Step-by-step explanation:

AB has length a and is divided by points P and Q into AP , PQ , and QB , such that AP = 2PQ = 2QB

A) Therefore, AP = 2QB

QB = AP/2

The midpoint of QB = QB/2 = (AP/2)/2 = AP/4

AP = 2PQ, Therefore PQ = AP/2

Since the length of AB = a

AB = AP + PQ + QB = a

AP + AP/2 + AP/2 = a

AP + AP = a

2AP = a

AP = a/2

The distance between point A and the midpoint of segment QB = AP + PQ + QB/2 = AP + AP/2 + AP/4 = 7/4(AP)

But AP = a/2

Therefore The distance between point A and the midpoint of segment QB =  7/4(a/2)= \frac{7}{8}a

B)

the distance between the midpoints of segments AP and QB = AP/2 + PQ + QB/2 = AP/2 + AP/2 + AP/4 = 5/4(AP)

But AP = a/2

Therefore the distance between the midpoints of segments AP and QB = 5/4(AP) = \frac{5}{4} *\frac{a}{2}=\frac{5}{8}a

7 0
3 years ago
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