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Ksenya-84 [330]
3 years ago
5

I need help ASAP!! If you know what you’re doing go ahead and answer but if you don’t, don’t even bother thanks

Mathematics
2 answers:
BaLLatris [955]3 years ago
7 0

Answer:

133.97 cm³

Step-by-step explanation:

The volume of a cone is given by:

V = \frac13 \pi r^2h

r is half the diameter, so 4 cm

h is 8 cm

So:

V= 1/3 * 3.14 * 16 * 8 ≈ 133.97 cm³

kipiarov [429]3 years ago
7 0
536 to the nearest hundredth
Solution: 3.14*r^2 *h/3
r: 8
h:3
3.14*8^2*8/3
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Jaime makes the following claim.
Sphinxa [80]

Jaime is incorrect, the angle does not depend on the radius of the circles.

<h3>Is Jaime correct?</h3>

Remember that an angle that defines an arc on a circle, does not depend on the radius of the circle.

So, if we have an angle with a measure of π/3 radians in a circle with a radius of 3 inches and an angle with a measure of π/3 radians in a circle with a radius of 6 inches, these two angles are exactly the same thing.

The radius of the circle only has an impact on the length of the arc defined by the angle.

So Jaime is clearly incorrect.

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7 0
2 years ago
At a sale, shirts were sold for $20 each. This price was 80% of their original price. What was the original price?
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Answer:

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7 0
3 years ago
This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex
noname [10]

L(x,y,z,\lambda)=10x+10y+2z+\lambda(5x^2+5y^2+2z^2-42)

L_x=10+10\lambda x=0\implies1+\lambda x=0

L_y=10+10\lambda y=0\implies1+\lambda y=0

L_z=2+4\lambda z=0\implies1+2\lambda z=0

L_\lambda=5x^2+5y^2+2z^2-42=0

\begin{cases}L_x=0\\L_y=0\\L_z=0\end{cases}\implies1+\lambda x=1+\lambda y=1+2\lambda z=0\implies x=y=2z

5x^2+5y^2+2z^2=5(2z)^2+5(2z)^2+2z^2=42z^2=42\implies z^2=1

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There are two critical points, at which we have

f\left(2,2,1\right)=42\text{ (a maximum value)}

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3 0
4 years ago
6= m - 7/8 HELLLLLLP
Oduvanchick [21]

Answer:

m =  6 7/8 or  55/8.

Step-by-step explanation:

6= m - 7/8

6 + 7/8 = m - 7/8 + 7/8

m =  6 7/8 or  55/8.

4 0
3 years ago
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Tcecarenko [31]

Answer:

          /\

\sqrt{20} /     \\sqrt{20}

     /         \

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Step-by-step explanation:

i hope this is right it took me 30 min for the ascii

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