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kotegsom [21]
3 years ago
15

Solve for z. z³ = 64 Enter your answer in the box. z =

Mathematics
1 answer:
zlopas [31]3 years ago
6 0

Answer:

z³ = 64

z³=4³

since power is equal, base will be same

z=4

Step-by-step explanation:

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38.6%

Step-by-step explanation:

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3 years ago
A rectangle has a width, w, equal to 6 less than the length, l. Which expressions represent ways to find the perimeter of the re
Irina-Kira [14]

Answer:

4L-12

Step-by-step explanation:

let's assume the length = L

then the width of the rectangle is L - 6

perimeter = 2× (a+b)

where "a" and "b" are the length and the width of the rectangle.

so perimeter = 2× (L + L - 6)

2 × ( 2L - 6)

4L - 12

5 0
3 years ago
V/-5+8=9 what does v equal
Sergeeva-Olga [200]
Subtract 8 from both sides and then multiply both sides by -5
V = -5
6 0
3 years ago
I’m confused and don’t have an angle tool to even try to do the question
yanalaym [24]
<h3>Answer:   40</h3>

=================================================

Explanation:

JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.

See the diagram below.

The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)

We know that JN = 60

Let x = JQ and y = QN

The ratio of x to y is x/y and this is 2/1

x/y = 2/1

1*x = y*2

x = 2y

Now use the segment addition postulate

JQ + QN = JN

x + y = 60

2y + y = 60

3y = 60

y = 60/3

y = 20

QN = 20

JQ = 2*y = 2*QN = 2*20 = 40

--------------

We have

JQ = 40 and QN = 20

We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.

7 0
3 years ago
Example 4:
oee [108]

Answer:

sorry but i need the points

Step-by-step explanation:

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3 years ago
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