The inequality 94 – 3 log2x ≤ 88 describes noise exposure level (in decibels) in terms of the number of hours, x, it takes to re
2 answers:
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Answer:
(5.097, 7.404)
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 40 - 1 = 39
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 39 degrees of freedom(y-axis) and a confidence level of . So we have T = 1.6849
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 6.25 - 1.154 = 5.096 hours
The upper end of the interval is the sample mean added to M. So it is 6.25 + 1.154 = 7.404 hours.
The answer is (5.097, 7.404)