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3 years ago

What roles did militias play in the American Revolution? Your answer:

Mathematics

1 answer:

Annette [7]3 years ago

8 0

Hey there! I'm happy to help!

A militia is a local army. During the Battle of Lexington and Concord, the local militia (called minutemen), the militia outnumbered the British at Concord and chased them all the way back to Boston. The militia aided in many American victories during the Revolutionary War.

I hope that this helps! Have a wonderful day! :D

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Factor 9y2 - 12y + 4.<br><br> (3 y - 2)(3 y + 2)<br> (3 y - 4)( y + 1)<br> (3 y - 2) 2

lozanna [386]

Answer:

(y - 2)²

Step-by-step explanation:

9y² - 12y + 4 ← is a perfect square of the form

(ax - b)² = a²x² - 2abx + b²

Compare like terms with 9y² - 12y + 4, thus

a² = 9 ⇒ a = 3

b² = 4 ⇒ b = 2 and

- 2ab = - 2 × 3 × 2 = - 12

Thus

9y² - 12y + 4 = (3y - 2)²

8 0

3 years ago

Which numbers below belong to the inequality check all that apply x/6 greater than equal to 9

grandymaker [24]

X/6 >= 9
x >= 6 x 9
x >= 54

Therefore, 60, 72 and 54 satisfies the inequality.

6 0

3 years ago

What is the length of the hypotenuse of a right triangle with legs or 5cm and 6cm

Oksana_A [137]

Answer:

hypotenuse = squareroot of 61 cm. which is approximately 7.81025 cm

Step-by-step explanation:

5 squared + 6 squared = hypotenuse squared

square root of (5 squared + 6 squared)= hypotenuse

6 0

2 years ago

Read 2 more answers

Why does the equation 3x+7=-3x+2+6x have no solution?

ale4655 [162]

3x+7=3x+2 (cancel equal terms)
7=2 ( the statement is false)

5 0

3 years ago

If a,b, and c are prime numbers, do (a+b)(a+b) and cc have a common factor that is greater than 1?

Tanya [424]

Answer:

1. Information is not sufficient

2. Information is not sufficient

Step-by-step explanation:

Question Modified

If a,b, and c are prime numbers, do (a+b) and c have a common factor that is greater than 1?

(1) a,b, and c are all different prime numbers

(2) c≠2

Explanation

1. Let's assume values of 1,3 and 5 to a, b, and c respectively

a + b = 1+3 = 4

4 and 5 do not have any common factor aside 1

Let's assume values of 1,3 and 2 to a,b and c respectively

a + b = 1+3 = 4

4 and 2 have a common factor of 2

So, the available information is not sufficient

Let's assume values of 2,7 and 3 to a b and c response

a + b = 2 + 7 = 9

9 and 3 have a common factor of 3

Also, let's assume values of 2,7 and 5 to a, b and c

a + b = 2 + 7 = 9

9 and 5 do not have a common factor

So, the available information is also not sufficient to answer the question.

3 0

3 years ago