Answer:
Between 15.95 ounces and 16.15 ounces.
Step-by-step explanation:
We have the following value m, being the mean, sd, being the standard deviation and n, the sample size:
m = 16.05
sd = 0.1005
n = 4
We apply the formula of this case, which would be:
m + - 2 * sd / (n ^ 1/2)
In this way we create a range, replacing we have:
16.05 + 2 * 0.1005 / (4 ^ 1/2) = 16.1505
16.05 - 2 * 0.1005 / (4 ^ 1/2) = 15.9495
Which means that 95% of all samples are between 15.95 ounces and 16.15 ounces.
The number 12 is missing in the data set.
<u>Step-by-step explanation</u>:
- The numbers are 9,12,16,18,23.
- The missing number is assumed to be 'x'
Mean = Sum of the integers / Total number of integers.
15 = (9+12+16+18+23+x) / 6
15 = (78+x) / 6
90 = 78+x
x = 90-78
x = 12
They are they same amount because 100 and 4 tens and 14 tens are the same
Answer:
d = √5 ≈ 2.24
Step-by-step explanation:
B is located at (1, 3) and B' is located at (3, 4)
Distance formula:
[tex] d = \sqrt{(xB' - xB)^2 + (yB' - yB)^2}[\tex]
replacing with the coordinates of the points:
[tex] d = \sqrt{(3 - 1)^2 + (4 - 3)^2}[\tex]
[tex] d = \sqrt{4 + 1}[\tex]
d = √5 ≈ 2.24
