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3 years ago

15

Please help, I don’t understand this

1 answer:

kondor19780726 [428]3 years ago

8 0

Answer:

same here

have a nice day

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A fountain holds 12,500 gallons of water. Joe wants to find how many liters that is. Which proportion could he use to solve for

DedPeter [7]

Answer:

The proportion <u>1 L : 0.26 gal = x L : 12500 gal</u>.

Step-by-step explanation:

Given:

A fountain holds 12,500 gallons of water.

1 L = 0.26 gal

Now, to get the proportion to solve for the number of litres.

$1\ L : 0.26\ gal = x\ L:12500\ gal$

$\frac{1\ L}{0.26\ gal} =\frac{x\ L}{12500\ gal}$

<em>On solving :</em>

$x=12500(\frac{1}{0.26})\ L$

Therefore, the proportion <u>1 L : 0.26 gal = x L : 12500 gal</u>.

4 0

4 years ago

Y=3x-5 y=-6x+4 system of equations

slega [8]

X=1, y=-2--------------------------

6 0

4 years ago

Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

3 years ago

What is the distance between the points (4,7) and (4,-5)?

elena-14-01-66 [18.8K]

$\sqrt{(x2-x1)^2+(y2-y1)^2} 

 \sqrt{(4-4)^2+(-5-7)^2} = 12 Units.$

Hope this loves.

5 0

4 years ago

Read 2 more answers

A. m = 10<br><br> B. m = 12<br><br> C. m = 9

mars1129 [50]

Answer:

C

Step-by-step explanation:

just took that

5 0

3 years ago