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4 years ago

Which property is illustrated by the equation -8+0=-8?

Mathematics

2 answers:

Anna35 [415]4 years ago

8 0

Answer:

Additive identity

Step-by-step explanation:

The reason why is any number added to 0 remains as the number it was before. So 3 + 0 = 3, 5 + 0 = 5.

sukhopar [10]4 years ago

5 0

Answer:

Step-by-step explanation:

Additive identity

-8+0= -

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Find the integral of 9^(6x)

vredina [299]

Answer:

(1/ 6 ln (9) ) x 9^6x + C

Step-by-step explanation:

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3 years ago

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True [87]

Answer:

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3 years ago

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Suppose that R and S are points on the number line.

zavuch27 [327]

-0.85714285714

Just divide 12 by -14

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3 years ago

With the ratio at 1:1, Point C appears to be the midpoint. Use the midpoint formula to ascertain (make sure of) whether Point C

Mila [183]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete because the coordinates of A, B and C were not given in the question.

However, the following explanation will guide you...

The midpoints, C of two point A and B is calculated as:

$C(x,y) = (\frac{x_1 + y_1}{2}, \frac{y_1 + y_2}{2})$

Where $(x_1, y_1)$ are the coordinates of A

and

$(x_2,y_2)$ are the coordinates of B

Take for instance, the given coordinates are

A(4,6); B(2,4) and C(3,5)

Then;

Plug in these values in the given formula:

$C(x,y) = (\frac{x_1 + y_1}{2}, \frac{y_1 + y_2}{2})$

$(3,5) = (\frac{4 + 2}{2}, \frac{6 + 4}{2})$

$(3,5) = (\frac{6}{2}, \frac{10}{2})$

$(3,5) = (3,5)$

In that case,

C is really the midpoint

To the b part: <em>Explaining why ratio 1:1 is used</em>

The reason is that both parts of the ratio are in equal proportion (1 and 1);

Because of this equal proportion, ration 1:1 is right to calculate the midpoint

4 0

3 years ago

In circle R with mZQRS = 66 and QR = 4 units find area of sector QRS. Round

Reika [66]

Answer:

$A_s=9.22\ units^2$

Step-by-step explanation:

<u>Area of a Circular Sector</u>

A circular sector is a shape formed by two radios and the part of the circumference they define. A central angle $\theta$ (in radians) is formed and the area of the sector is given by

$\displaystyle A_s=\frac{1}{2}\theta\cdot r^2$

The dimensions provided in the questions are

$\theta=66^o$

$r=4\ units$

Converting the angle to radians

$\theta=66\cdot \pi/180=1.152\ rad$

Now we compute the area

$\displaystyle A_s=\frac{1}{2}\cdot 1.152\cdot 4^2$

$A_s=9.22\ units^2$

6 0

3 years ago