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3 years ago

How many digits of Pi had the Guinness World Record holder memorized?

Mathematics

2 answers:

Aleonysh [2.5K]3 years ago

8 0

correct answer to your question would be 70,000

3241004551 [841]3 years ago

4 0

The most decimal places of Pi<span> memorised is 70,000.</span>

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What is the least common multiple of 16, 24 and 30?

r-ruslan [8.4K]

All of the numbers are even so 2

Answer: 2

6 0

4 years ago

Read 2 more answers

A standard weight known to weigh 10 grams. Some suspect bias in weights due to manufacturing process. To assess the accuracy of

notsponge [240]

Answer:

a) The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams

b) 49 measurements are needed.

Step-by-step explanation:

Question a:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.98}{2} = 0.01$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.01 = 0.99$ , so Z = 2.327.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 2.327\frac{0.0003}{\sqrt{5}} = 0.00031$

The lower end of the interval is the sample mean subtracted by M. So it is 10.0044 - 0.00031 = 10.00409 grams

The upper end of the interval is the sample mean added to M. So it is 10 + 0.00031 = 10.00471 grams

The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams.

(b) How many measurements must be averaged to get a margin of error of +/- 0.0001 with 98% confidence?

We have to find n for which M = 0.0001. So

$M = z\frac{\sigma}{\sqrt{n}}$

$0.0001 = 2.327\frac{0.0003}{\sqrt{n}}$

$0.0001\sqrt{n} = 2.327*0.0003$

$\sqrt{n} = \frac{2.327*0.0003}{0.0001}$

$(\sqrt{n})^2 = (\frac{2.327*0.0003}{0.0001})^2$

$n = 48.73$

Rounding up

49 measurements are needed.

7 0

3 years ago

Kaitlin has been given a list of bands and asked to place a vote. Her vote must have the names of her favorite and second favori

umka2103 [35]

Complete question :

Kaitlin has been given a list of 5 bands and asked to place a vote. Her vote must have the names of her favorite and second favorite bands from the list. How many different votes are possible?

Answer:

20 different votes

Step-by-step explanation:

Total number of bands = 5

To select her favorite ; she chooses 1 from the five ;

Number of bands left = 4

From. The 4 she chooses one ; which is her second favorite

Number of different votes possible :

Favorite selection * second favorite selection

(5 * 4) = 20 different votes.

3 0

3 years ago

Help !!! with 14 please :))

BartSMP [9]

Since p is an obtuse angle
& that it's between two acute angles

3 0

3 years ago

These kittens get 1 can of cat food a day. If each can holds 6 ounces of food, how many ounces of food do they eat in one week?

Paladinen [302]

If 6=1 then 6x7= 42 so 42 oz of food per week

5 0

3 years ago