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grin007 [14]
3 years ago
5

1

Mathematics
1 answer:
photoshop1234 [79]3 years ago
6 0

Answer:

Pentagon and I think the area is 19.89 so if you round it, that will be 19.9

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What is (-2xy^3z^-2)^3(2x^2y^4z)^-2 simplified?
ser-zykov [4K]

Answer: 3 23 divided by 22 = 2(3 - 2) = 21 = 2 think it’s 2

Step-by-step explanation: Changes made to your input should not affect the solution:

(1): "^-2" was replaced by "^(-2)".

(2): "y4" was replaced by "y^4".

STEP

1

:

Equation at the end of step 1

(((0-((2x•(y3))•z))-2)3)•(((2x2•y4)•z)-2)

STEP

2

:

Equation at the end of step

2

:

(((0 - (2xy3 • z)) - 2)3) • (2)(-2)x(-4)y(-8)z(-2)

STEP

3

:

STEP

4

:

Pulling out like terms

4.1 Simplify ( -2xy3z-2 )3

Put the exponent aside and simplfy the base by pulling out like factors :

-2xy3z-2 = -2 • (xy3z+1)

Remember the 4th law of exponents : (a • b)m= am• bm

Retract the exponent and apply the 4th law to the simplified base: ( -2 • (xy3z+1) )3 = (-2)3 • (xy3z+1)3

Trying to factor as a Sum of Cubes:

4.2 Factoring: xy3z+1

Put the exponent aside, try to factor xy3z+1

Theory : A sum of two perfect cubes, a3 + b3 can be factored into :

(a+b) • (a2-ab+b2)

Proof : (a+b) • (a2-ab+b2) =

a3-a2b+ab2+ba2-b2a+b3 =

a3+(a2b-ba2)+(ab2-b2a)+b3=

a3+0+0+b3=

a3+b3

Check : 1 is the cube of 1

Check : x 1 is not a cube !!

Ruling : Binomial can not be factored as the difference of two perfect cubes

Dividing exponents:

4.3 23 divided by 22 = 2(3 - 2) = 21 = 2

Final result :

-2 • (xy3z + 1)3

————————————————

x12y24z6

4 0
3 years ago
Read 2 more answers
Solve all these 4 please
DIA [1.3K]

Answer:

Step-by-step explanation:

7 0
3 years ago
If that is = a, find the value of a + 1 over a<br><img src="https://tex.z-dn.net/?f=3%20-%20%20%5Csqrt%7B5%7D%20" id="TexFormula
Doss [256]

Answer:

7+√5/4

Step-by-step explanation:

if that is = a, find the value of a + 1 over a

​Given that a = 3 - √5

a+1/1 = (3-√5)+1/3 - √5

4-√5/3 - √5

Rationalize

4-√5/3 - √5 * 3+√5/3 + √5

= 12 +4√5-3√5-√25/9-5

= 12+√5-5/4

= 7+√5/4

Hence the requred answer is  7+√5/4

6 0
3 years ago
If f(x)=x+7 and g(x)=1/x-13 what is the domain of (f times g)(x)
umka21 [38]

(f\cdot g)(x)=f(x)\cdot g(x)\\\\\text{We have}\ f(x)=x+7\ \text{and}\ g(x)=\dfrac{1}{x-13}.\\\\\text{Substitute}\\\\(f\cdot g)(x)=(x+7)\cdot\dfrac{1}{x-13}=\dfrac{x+7}{x-13}\\\\\text{The domain:}\\\\x-13\neq0\qquad\text{add 13 to both sides}\\\\x\neq13\\\\Answer:\ \boxed{x\in\mathbb{R}-\{13\}}\to\boxed{\text{All real numbers except 13}}

7 0
3 years ago
What’s the answer for this
Svetradugi [14.3K]
The answer is D) 15+(-8)
6 0
4 years ago
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