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OLga [1]
3 years ago
8

Pls do this one i have quiz at this so ya pla do it i only have 20 minutes pls​

Mathematics
1 answer:
steposvetlana [31]3 years ago
5 0

Answer:

Answers for the question

(1.)320cm3 (2.)144cm3. (3.)330cm3. (4.)160cm3.(5.)336cm3. (6.)1440cm3. (7.)7500cm3. (8.)20000. (9.)1500000

please the three besides cm is cm raise the power three meaning cm-cube

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8n^2-4(7m^3+5n^2)<br> help
Rasek [7]
Hello there!


8m² - 4(7m³ + 5n²)

You wanna start by using the distributive property

=8n² - (-4)(7m³) + (-4)(5n²)

= 8n² - 28m³ - 20n²

= -28m³ - 12m²
7 0
2 years ago
What is the least positive integer divisible by each of the first five composite numbers
Sonbull [250]

Answer:

the answer is 360. the first composite numbers are 4,6,8,9,10

and all the numbers above are divisible by 360

360÷4=90

360÷6=60

360÷8=45

360÷9=40

360÷10=36

6 0
3 years ago
Hiii please help i’ll give brainliest:)
djverab [1.8K]

Answer:

Geographic features of ancient Greece.

Step-by-step explanation:

Greece has all of those attributes.

6 0
2 years ago
Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse
Drupady [299]

Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

a(a'(d)) = a'(a(d)) = d

Step-by-step explanation:

Given

a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

7 0
2 years ago
3х - 3 = -12<br> What is the solution to this equation?
Lapatulllka [165]
3x-3=-12

3x=-9

X=-3


I am in calculus. Algebra is easy
5 0
2 years ago
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