Answer:
120 degrees
Step-by-step explanation:
The total distance that was covered by the sprinter in Kilometers is:
<h3>How much is the total distance covered?</h3>
To obtain the total distance covered by the sprinter, we need to first realize that 1 Km is equal to 1000 meters. That said, the question above requires us to change 2400 meters to kilometers.
Thus we will have:
2400 Meters * 1 km / 1000 meters
= 2.4 km
So, the total distance covered by the sprinter in kilometers is 2.4
Learn more about meter conversions here:
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.3478 is the answer, round however you like
It should be noted that Polygon 3 and polygon 4 are similar to polygon 1.
<h3>
What exactly is polygon?</h3>
In geometry, it should be noted that a polygon is a plane figure which is described by a finite number of straight line segments that are connected in order to form a closed polygonal chain.
In this case, the bounded plane region, the bounding circuit, may be called a polygon. Also, a similarity transformation is the conformal mapping whose transformation matrix are identical.
In this case, it should be noted that Polygon 3 and polygon 4 are similar to polygon 1.
Learn more about polygon on:
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Answer:
The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=%5Cpi%20%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In which
z is the zscore that has a pvalue of
.
For this problem, we have that:
![n = 55, \pi = \frac{24}{55} = 0.4364](https://tex.z-dn.net/?f=n%20%3D%2055%2C%20%5Cpi%20%3D%20%5Cfrac%7B24%7D%7B55%7D%20%3D%200.4364)
93% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
![\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 - 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.3154](https://tex.z-dn.net/?f=%5Cpi%20-%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.4364%20-%201.81%5Csqrt%7B%5Cfrac%7B0.4364%2A0.5636%7D%7B55%7D%7D%20%3D%200.3154)
The upper limit of this interval is:
![\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 + 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.5574](https://tex.z-dn.net/?f=%5Cpi%20%2B%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.4364%20%2B%201.81%5Csqrt%7B%5Cfrac%7B0.4364%2A0.5636%7D%7B55%7D%7D%20%3D%200.5574)
The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).