<span>The
third root of the given complex number 27(cos(pi/5)+isin(pi/5)) is <span>3(cos(pi/15)+i sin(pi/15))
</span>The solution would be like this
for this specific problem:</span>
<span>2^5 =
32 so you need a 2 out front the 5th root of cos(x) + i sin(x) is
cos(x/5) + i sin(x/5). Additionally, 5 roots are located at even
intervals around the circle. They are spaced every 2 pi/5 or 6 pi/15 radians.
</span>
<span>Roots
are located at pi/15, pi/15+ 10pi/15 = 11 pi/15 and pi/15+ 20pi/15 = 21 pi/15
(or 7 pi /5 ).</span>
Answer: 6456
Step-by-step explanation:
Ratio of yes to no= 7:5
Number if yes= 3766
Since total number of yes is 3766. To find the total number of votes, 3766 / (7/7+5)
= 3766/ (7/12)
= 3766 × 12/7
= 45192/7
= 6456
There were 6456 total votes
Answer:
a) 
b) 
c) 
Step-by-step explanation:
<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.
This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.
Then write the polynomial in factored form.

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.
<u>For question b, do the same procedure</u>.
Degree: 3
Zeros: -5/2, 4/5, 6.
The factors are

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<u>Finally for the question c we have</u>
Degree: 5
Zeros: -3, 1, 4, -1
Multiplicity 2 in -1

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Answer:
1/2
Step-by-step explanation: