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gavmur [86]
3 years ago
8

What is the answer 8.325 divide by 10 to the 3 power?

Mathematics
1 answer:
horsena [70]3 years ago
4 0

Answer:

Step-by-step explanation:

0.008325

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Is the following relation a function? <br><br> Yes<br> Or<br> No
WITCHER [35]
Yes, that relation is a function. It has no repeating x values
6 0
3 years ago
Read 2 more answers
I legit do not know which it is.
nexus9112 [7]

Given:

The inequality is

c\leq 7

Where, c is the number of cars in the parking lot.

To find:

The graph for the given inequality.

Solution:

We have,

c\leq 7

Here, the value of c can be any real number less than or equal to 7. But c is the number of cars, so c must be a non-zero integer.

Since, all the non-zero integer values less than or equal to 7 are included in the solution set, therefore, c = 0,1, 2,3,4, 5,6,7.

In the graph of the given inequality, there are close circles on  0,1, 2,3,4, 5,6,7 as shown in option D.

Therefore, the correct option is D.

4 0
3 years ago
Veronica works at a music store last week she sold five more than three times the number of headphones that she sold this week.
svet-max [94.6K]

Answer:

14 headphones

Step-by-step explanation:

Use algebraic manipulation. Let x be the number of headphones sold this week:

89 = x + (3x + 5)

Combine like terms:

89 = 4x + 5

Get the x's on one side:

84 = 6x

Divide:

14 = x

So, Veronica sold 14 headphones this week.

5 0
2 years ago
A researcher takes a simple random sample of 83 homes in a city and finds that the mean square footage is 1628 with a standard d
Anna [14]

Answer: (1583.63, 1672.37)

Step-by-step explanation:

Given : Sample size : n= 83

Sample mean : \overline{x}=1628

Sample standard deviation : \sigma=243

The population standard deviation(\sigma) is unknown .

The confidence interval for population mean :

\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}

For 90% confidence , significance level =\alpha=1-0.90=0.10

Using t-distribution table , Critical t-value = t_{(\alpha/2, n-1)}=t_{0.05,82}=1.6636

, where n-1 is the degree of freedom.

Now ,  90% confidence interval for the mean square footage of all the homes in that city will be :-

1628\pm (1.6636)\dfrac{243}{\sqrt{83}}\\\\ 1628\pm (1.6636)(26.672715)\\\\\\\\\approx1628\pm 44.37\\\\=(1628- 44.37,\ 1628+ 44.37)\\\\=(1583.63,\ 1672.37)

Hence, the 90% confidence interval for the mean square footage of all the homes in that city = (1583.63, 1672.37)

7 0
3 years ago
What is the IQR (interquartile range) of the data set? 33, 37, 45, 61, 64, 67
Nataly_w [17]

solution is first os all find median

median is( 45+61)/2=53

find median of no in left of 53

it is 37

find median of no in right of 53

it is 64

now interquartile range=64-53=27

4 0
3 years ago
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