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2 years ago

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the width of a rectangle is 2 more than 4 times its length. The perimeter of the rectangle is 24 centimeters. Find the width of

the rectangle

1 answer:

alekssr [168]2 years ago

4 0

Answer:

Step-by-step explanation:

W=4L+2, L=(W-2)/4

P=2(L+W)=24

2((W-2)/4+W)=24

2(5W-2)/4=24

5W-2=48

5W=50

W=10

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Answer:

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Step-by-step explanation:

We are given that

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Integrating on both sides then, we get

$lny=kt+C$

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Substitute the values then , we get

$ln 200=k(0)+C$

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Substitute the value of C then we get

$ln y=kt+ln 200$

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$ln\frac{y}{200}=kt$

$\frac{y}{200}=e^{kt}$

$y=200e^{kt}$

Differentiate w.r.t

$y'=200ke^{kt}$

Substitute the given condition then, we get

$100=200ke^{0}=200 \;because \;e^0=1$

$k=\frac{100}{200}=\frac{1}{2}$

$y=200e^{\frac{t}{2}}$

Substitute t=2

Then, we get $y=200e^{\frac{2}{2}}=200e$

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