Can u pretty please help me it’s late I’m really struggling

Please help!!!! got to do this for math

Umnica [9.8K]

Answer:

$11\sqrt{2}-5\sqrt{7}$

7 0

3 years ago

In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank

fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) $Amount \ of \, water \ remaining \ in \, the \ tank \ is \ \frac{x^3(6-\pi) }{6}$

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The volume of the sphere = $\frac{4}{3} \pi r^3$

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = $\frac{4}{3} \pi \frac{x^3}{8}$ = $\frac{1}{6} \pi x^3$

For tank B

Volume of tank = x³

The volume of the spheres = $8 \times \frac{4}{3} \pi r^3$

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = $8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}$

For tank C

Volume of tank = x³

The volume of the spheres = $64 \times \frac{4}{3} \pi r^3$

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = $64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}$

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The volume of the spheres = $512 \times \frac{4}{3} \pi r^3$

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = $512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}$

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = $x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}$

$Amount \ of \ water \, remaining \, in \, the \ tank = \frac{x^3(6-\pi) }{6}$ .

5 0

3 years ago

Kristin and her family left their campsite to take a bike ride. They biked 5 miles west and then 12 miles north. How far are the

pickupchik [31]

Answer:

they are 17 miles away from their campsite.

Step-by-step explanation:

we get the answer by adding the miles traveled north to the miles traveled west, and we get the total number of miles they traveled away from their campsite.

5 + 12 = 17

8 0

3 years ago

Tryna figure this out

kaheart [24]

Answer:

9pi approximately 28

Step-by-step explanation:

we have the formula - pi r^2

which we know the diameter is 6 m and the surface is a semi circle

the radius is 3 so then we have pi 3^2

which becomes 9pi which is about 28.2

rounding to 28

hope this helps!!

7 0

3 years ago

1. Your average daily balance on your charge card for the month of July is $855.28. If your card carries an annual interest rate

Nat2105 [25]

1. Using "exact" interest, your charge will be
.. I = Prt
.. I = $855.28*0.154*(31/365)
.. I = $11.19

2. It will take 52.01 months to pay off the loan.

3. Your payment on 15,250 for 4 years will be $363.41. The effective interest rate that payment represents on a loan of $15,000 is 7.604%

4. Todd's monthly payments will be $409.06, so his total outlay will be
.. tax+license + down payment + loan repayment
.. = 1200 +1000 +48*409.06
.. ≈ $21,835

4 0

3 years ago