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prohojiy [21]
3 years ago
12

How could you use 1/8 measuring cup to measure 1/4 cups of water ​

Mathematics
2 answers:
RSB [31]3 years ago
8 0

Answer:

1/2 cup

Step-by-step explanation:

Two 1/8 cups = 1/4 cup Half of 1/2 cup = 1/4 cup.

sp2606 [1]3 years ago
8 0
You could use the 1/8 measuring cup twice because that would be 2/8 which is the equivalent to 1/4 with GCF of 2
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Write and equation of the line that passes through the point (2,-6) and is parallel to the line x-2y=8
mestny [16]

Answer:

y=0.5x-7

Step-by-step explanation:

x-2y=8

2y=x-8

y=0.5x-4 m1=0.5

m1=m2=0.5 - the slope for parallel lines are equaly

y=m2x+b

-6=0.5*2+b

b=-7

y=0.5x-7

5 0
3 years ago
Solve for the value of k
wel

Answer:

k=13

Step-by-step explanation:

3k+6+4k-7+90=180

7k+89=180

k=180-89/7

k=13

8 0
3 years ago
For which equation is y = 7 a solution?
natali 33 [55]

Answer:

B

Step-by-step explanation:

11+7=18

3 0
3 years ago
Read 2 more answers
If 5 more than twice a number is equal to 2 less<br> than 3 times the number, what is the number?
Vlada [557]

Answer:

7

Step-by-step explanation:

The following equation can be derived from the question

Let x = unknown number

5 + 2x = 3x - 2

collect like terms

5 + 2 = 3x - 2x

x = 7

4 0
3 years ago
A sector of a circle makes a 127° angle at its centre. If the arc of the sector has length 36 mm, find
Veseljchak [2.6K]

Answer:

Approximately 68.5\; \rm mm.

Step-by-step explanation:

Convert the angle of this sector to radians:

\begin{aligned}\theta &= 127^{\circ} \\ &= 127^{\circ} \times \frac{2\pi}{360^{\circ}} \\ &\approx 2.22\end{aligned}.

The formula s = r\, \theta relates the arc length s of a sector of angle \theta (in radians) to the radius r of this sector.

In this question, it is given that the arc length of this sector is s = 36\; \rm mm. It was found that \theta = 2.22 radians. Rearrange the equation s = r\, \theta to find the radius r of this sector:

\begin{aligned} r&= \frac{s}{\theta} \\ &\approx \frac{36\; \rm mm}{2.22} \\ &\approx 16.2\; \rm mm\end{aligned}.

The perimeter of this sector would be:

\begin{aligned}& 2\, r + s \\ =\; & 2 \times 16.2\; {\rm mm} + 36\; {\rm mm} \\ =\; & 68.5\; \rm mm\end{aligned}.

8 0
3 years ago
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