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3 years ago

8

Someone please help explain how I'm supposed to solve these? The next quarter is starting tmr.

1 answer:

Greeley [361]3 years ago

3 0

Answer:

10=+hsh

Step-by-step explanation:

i ahte math

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What shape best describes the cross-section cut perpendicular to the base of a right rectangular prism? O Parallelogram Trapezoi

masya89 [10]

The cross-section perpendicular to the base of a right rectangular prism is a rectangle.

<h3>What is a three dimensional shape?</h3>

A shape or a solid that has three dimensions that is length, width and height is called a 3D shape. 3D shapes have faces, edges, and vertices. Examples are cylinder, cone, prism, pyramid.

A shape that has two dimensions is called a 2D shape. 2D shapes have breadth and length.

The cross-section perpendicular to the base of a right rectangular prism is a rectangle.

Find out more on three dimensional shape at: brainly.com/question/326906

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8 0

2 years ago

Simply (tan^2 x - sec^2 x)(sin^2 x + cos^2 x)

kati45 [8]

we can use pythagorean identieis

remember that $sin^2(x)+cos^2(x)=1$

also remember that $tan(x)=\frac{sin(x)}{cos{x}}$ and $sec(x)=\frac{1}{cos(x)}$

so if we take $sin^2(x)+cos^2(x)=1$ and divide both sides by $cos^2(x)$ we get

$\frac{sin^2(x)}{cos^2(x)}+\frac{cos^2(x)}{cos^2(x)}=\frac{1}{cos^2(x)}$

$(\frac{sin(x)}{cos(x)})^2+1=(\frac{1}{cos(x)})^2$

$tan^2(x)+1=sec^2(x)$

subtracting $1+sec^2(x)$ from both sides

$tan^2(x)-sec^2(x)=-1$

now subsitute into original problem

$\frac{tan^2(x)-sec^2(x)}{sin^2(x)+cos^2(x)}=$

$\frac{-1}{1}=$

$-1$

the answer is -1

6 0

3 years ago

For a crane to lift the beam shown to the right, the beam and the two support cables must form an isosceles triangle with heigh

Fittoniya [83]

Answer:

The total length of the two cables is $2\sqrt{145}\ units$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

In the right triangle ABD

Applying the Pythagoras Theorem

$AB^{2}=BD^{2}+AD^{2}$

substitute the given values

$AB^{2}=9^{2}+8^{2}$

$AB^{2}=145$

$AB=\sqrt{145}\ units$

Remember that

AB=AC ----> because ABC is an isosceles triangle

so

The total length of the two cables is equal to

$AB+AC=2AB=2\sqrt{145}\ units$

3 0

3 years ago

two circles intersect each other in A and C. O the centre of the smaller circle, lies on circumference of the bigger circle D is

olchik [2.2K]

Answer:

ss

Step-by-step explanation:

s

5 0

3 years ago

Help me with just ONE question. Please

Novay_Z [31]

A) by completing the square... X^2-8x+16+20-16 = (x^2-4)^2 +20-16=(x^2-4)+4

B) Since the coefficient of x^2 is positive, it is a quadratic function which increases positively. You know that it will always be above the x axis and therefore positive since the vertex is at (4,4) and increasing

4 0

4 years ago