Show that if p(a) ⊂ p(b) then a ⊂ b.
<span>I will assume p() means power set. </span>
<span>proof: let x∈a, then {x} ∈ p(a) and so by hypothesis {x} ∈ p(b). However {x} could not be in p(b) unless x∈b. This shows that each element of a is an element of b and hence a ⊂ b.
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I believe the answer is A. 20, 30, 40 is NOT a pythagorean triple.
Answer:
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