Answer:
- <u>59.0891 g (rounded to 4 decimal places)</u>
Explanation:
<em>Half-life time</em> of a radioactive substance is the time for half of the substance to decay.
Thus, the amount of the radioactive substance that remains after a number n of half-lives is given by:
Where:
- A is the amount that remains of the substance after n half-lives have elapses, and
- A₀ is the starting amount of the substance.
In this problem, you have that the half-live for your sample (polonium-210) is 138 days and the number of days elapsed is 330 days. Thus, the number of half-lives elapsed is:
- 330 days / 138 days = 2.3913
Therefore, the amount of polonium-210 that will be left in 330 days is:
Answer:
3.1415926535 8979323846 2643383279 50288419716939937510 5820974944 5923078164 06286208998628034825 3421170679 8214808651 32823066470938446095 5058223172 5359408128 48111745028410270193 8521105559 6446229489 54930381964428810975 6659334461 2847564823 37867831652712019091 4564856692 3460348610 4543266482.
Step-by-step explanation:
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Answer:
Option C) is correct
That is t=StartFraction p Over s Subscript 1 Baseline minus s Subscript 2 Baseline EndFraction
It also can be written as 
Step-by-step explanation:
Given equation can be written as below:

Now to solve the equation for t:

Taking common term t outside on RHS we get


Rewritting the above equation as below

Therefore option C) is correct
That is t=StartFraction p Over s Subscript 1 Baseline minus s Subscript 2 Baseline EndFraction
It also can be written as 
Y=140 because U have to go 35 divided by 2 and 8 times 17.5