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fomenos
2 years ago
5

Add the equations.2x-3y = -1+ 3x + 3y= 26​

Mathematics
1 answer:
hichkok12 [17]2 years ago
8 0

Answer:

The answer in the procedure

Step-by-step explanation:

we have

2x-3y=-1 ----> equation A

3x+3y=26 --> equation B

Solve the system by elimination

Adds equation A and equation B

2x-3y=-1

3x+3y=26

----------------

2x+3x=-1+26

5x=25

x=25/5

x=5

Find the value of y

substitute the value of x in equation A or equation B and solve for y

2(5)-3y=-1

10-3y=-1

3y=10+1

y=11/3

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Answer:

16

Step-by-step explanation:

6n is 6 times 3 if n is 3. 6 times 3 is 18. Minus 2 is 16.

Hope this helps! If it does, please mark me brainliest. Thank you! ;)

4 0
2 years ago
All the answers please on paper and work
REY [17]
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7 0
3 years ago
Solve st + 3t = 6 for s
vaieri [72.5K]

st + 3t = 6 for s

Subtract 3t to both sides

st + 3t  - 3t = 6 - 3t

Simplify

st = 6 - 3t

Divide both sides by t

st/t = (6-3t)/3

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s = 6/3 - 3t/3

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6 0
3 years ago
Rewrite the point-slope equation in slope-intercept form: y - 3 = 2(x + 4)
Olin [163]

Answer:

y = 2x + 11

Step-by-step explanation:

y - 3 = 2(x + 4)      

y - 3 = 2*x + 2*4

y -3 = 2x + 8

y     = 2x + 8 +3

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7 0
2 years ago
Given csc(A) = 60/16 and that angle A is in Quadrant I, find the exact value of sec A in simplest radical form using a rational
Katarina [22]

Answer:

\displaystyle \sec A=\frac{65}{63}

Step-by-step explanation:

We are given that:

\displaystyle \csc A=\frac{65}{16}

Where <em>A</em> is in QI.

And we want to find sec(A).

Recall that cosecant is the ratio of the hypotenuse to the opposite side. So, find the adjacent side using the Pythagorean Theorem:

a=\sqrt{65^2-16^2}=\sqrt{3969}=63

So, with respect to <em>A</em>, our adjacent side is 63, our opposite side is 16, and our hypotenuse is 65.

Since <em>A</em> is in QI, all of our trigonometric ratios will be positive.

Secant is the ratio of the hypotenuse to the adjacent. Hence:

\displaystyle \sec A=\frac{65}{63}

6 0
3 years ago
Read 2 more answers
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