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Ber [7]
3 years ago
13

Max has 5 apples he gives away 2 How many apples does he have left

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
4 0
If max starts with 5 apples and then gives away too hes subtracting 2 so he has 3 left
equation: 5-2=3
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Find x if AB = 9, BC = 2x - 5,<br> and AC = x + 9
Oxana [17]

Answer:

x = 5

Step-by-step explanation:

Using the fact that line segments AB and BC are parts of the whole line segment AC, we can write the following equation:

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Now, using the given values, we can substitute in for the equation and solve for x:

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3 years ago
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Two sides of a triangle are equal in length and double the length of the shortest side. The perimeter of the triangle is 36 inch
chubhunter [2.5K]

Answer:

Two equal sides = 14.4 inches each

Shortest side = 7.2 inches

Step-by-step explanation:

a + b + c = 36

a = b

a = 2c

then:

c = a/2

a + a + a/2 = 36

2a + a/2 = 36

4a/2 + a/2 = 36

5a/2 = 36

a = 2*36/5

a = 72/5

a = 14.4

a = 2c

14.4 = 2*c

c = 14.4/2

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Check:

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3 0
3 years ago
You want to place a towel bar that is 24 1/4 centimeters long in the center of a door that is 70 1/3 centimeters wide. How far s
Aleksandr [31]

Answer:

The towel bar should be placed at a distance of 23\frac{1}{24}\ cm from each edge of the door.

Step-by-step explanation:

Given:

Length of the towel bar = 24\frac14\ cm

Now given length is in mixed fraction we will convert in fraction.

To Convert mixed fraction into fraction Multiply the whole number part by the fraction's denominator, then Add that to the numerator, then write the result on top of the denominator.

24\frac14\ cm can be Rewritten as \frac{97}{4}\ cm

Length of the towel bar =  \frac{97}{4}\ cm

Length of the door = 70 \frac13\ cm

70 \frac13\ cm can be Rewritten as \frac{211}{3}\ cm

Length of the door = \frac{211}{3}\ cm

We need to find the distance bar should be place at from each edge of the door.

Solution:

Let the distance of bar from each edge of the door be 'x'.

 So as we placed the towel bar in the center of the door it divides into two i.e. '2x'

Now we can say that;

\frac{97}{4}+2x=\frac{211}{3}\\\\2x=\frac{211}{3}-\frac{97}{4}

Now we will take LCM to make the denominators common we get;

2x=\frac{211\times4}{3\times4}-\frac{97\times3}{4\times3}\\\\\\2x= \frac{844}{12}+\frac{281}{12}

Now denominators are common so we will solve the numerators.

2x =\frac{844-291}{12}\\\\2x=\frac{553}{12}\\\\x=\frac{553}{12\times2} =\frac{553}{24}

Or x=23\frac{1}{24}\ cm

Hence The towel bar should be placed at a distance of 23\frac{1}{24}\ cm from each edge of the door.

8 0
3 years ago
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