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kodGreya [7K]
3 years ago
11

The equation tan(55) = 15/b can be used to find the length of line AC.what is the length of line AC round to the nearest 10th 3.

0in 9.8in 10.5n 12.8i
Mathematics
2 answers:
umka21 [38]3 years ago
8 0

Answer:

C

Step-by-step explanation:

ed2020

Nadusha1986 [10]3 years ago
7 0

Answer:

10.5 in

Step-by-step explanation:

Given

tan(55) = \frac{15}{b}

Required

Find length AC

The question is not detailed enough; so, I'll assume that b represents line AC.

Having said that;

We start by multiplying both sides by b

tan(55) = \frac{15}{b}

b * tan(55) = \frac{15}{b} * b

b * tan(55) =15

Divide both sides by tan(55)

\frac{b * tan(55)}{tan(55)} = \frac{15}{tan(55)}

b = \frac{15}{tan(55)}

Find tan(55)

b = \frac{15}{1.42814800674}

b = 10.5031130731

b = 10.5  <em>(Approximated)</em>

<em />

Length AC is 10.5

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This is Q.a

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3 years ago
Plsss help !!
Gennadij [26K]

Answer:

carnation $2.50; rose $3.00

Step-by-step explanation:

Let c = price of 1 carnation.

Let r = price of 1 rose.

3c + 5r = 22.5

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Subtract the se3cond equation from the first equation.

3r = 9

r = 3

Now substitute r = 3 in the first equation and solve for c.

3c + 5r = 22.5

3c + 5(3) = 22.5

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5 0
2 years ago
List the integers that satisfy both these inequalities, 2x+9 -12
Flura [38]

Answer:

x < -10.5

Step-by-step explanation:

list the integers that satisfy both these inequalities, 2x+9 <-12

Subtract 9 from  both sides;

2x +9 - 9 < -12-9

2x < -21

x < -21/2

x < -10.5

<em>Hence all the integers are values of x less than 10.5</em>

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4 0
2 years ago
Please I need the polynomial for this problem, if you don’t know then don’t answer! Wrong answers will be reported
babymother [125]

Answer:

Area = (36π - 12πx + x²π) mm²

Step-by-step explanation:

Given that,

radius of lense = 6mm

Length from outer layer of pupil to lense = x mm

Radius of pupil = 6 - x mm

<h3>Formula to calculate area of pupil</h3><h3> Area = π r²</h3>

<em> where r is radius of pupil</em>

Area = π (6 -x)²

Area = π (6² -2(6)(x) + x²)

Area = π (36 -12x +x²)

Area = (36π - 12πx + x²π) mm²

So, the polynomial in standard form that represent the area of pupil in terms of π =  (36π - 12πx + x²π) mm²

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3 years ago
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Phantasy [73]
1=104 2=76 3=104 4=76 5=104 6=76 7=104 8=76
8 0
2 years ago
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