Jane, Jasmine, and Jocelyn have record collections. Jane has 3 times as many records as Jocelyn has. Jasmine has 2 more than twi
ce the number Jocelyn has. Together the three girls have 56 records. How many records does each girl have?
1 answer:
X = jane, y = jasmine, z = jocelyn
x + y + z = 56
x = 3z
y = 2z + 2
3z + 2z + 2 + z = 56
6z + 2 = 56
6z = 56 - 2
6z = 54
z = 54/6
z = 9 <==== jocelyn
x = 3z
x = 3(9)
x = 27 <=== jane
y = 2z + 2
y = 2(9) + 2
y = 18 + 2
y = 20 <=== jasmine
You might be interested in
Answer:
32
Step-by-step explanation:
100: 25
4:1
x : 8
(8x 4) : 8
32: 8
ans 32
1/16 cup..........................1 tablespoon
1 1/2= 3/2 cups................x tablespoons
1/16*x=3/2
x= 3/2 : 1/16=3/2*16= 24 tablespoons he needs
well i got
x+4/x+1
when i calculated it
The answer fam is.......... "b.up"