All categories

3 years ago

A snail moves 18 millimeters every 24 seconds. What is the snail's rate of speed ?

Mathematics

2 answers:

andrey2020 [161]3 years ago

4 0

Answer:

0.75m/s

Step-by-step explanation:

<em>Speed formula: ⇒ $S=\frac{V}{T}$ </em>

<em>Divide by the numbers from left to right.</em>

<em>0.75m/s is the correct answer.</em>

<em>I hope this helps you, and have a wonderful day!</em>

mario62 [17]3 years ago

3 0

<h3>Answer:</h3>

$\frac{3}{4}$ millimeter per second

<h3>Explanation:</h3>

You simply need to divide $\frac{18}{24}$ . This is a fraction, so you can just simplify it.

Divide the numerator and the denominator each by 6, which is the greatest common factor. $\frac{\frac{18}{6}}{\frac{24}{6}} = \frac{3}{4}$

This is as simple as the result can get, so $\frac{3}{4}$ millimeter per second is the final answer.

You might be interested in

120,540,000 word form

tamaranim1 [39]

Answer:

one hundred twenty million five hundred forty thousand

3 0

3 years ago

Read 2 more answers

50 BIG POINTS! Help me on math please! @ Apologiabiology, @ Bookishfairy73

nekit [7.7K]

Rate of change is also knkown as slope which is found by
$\frac{y2-y1}{x2-x1}$ =slope if you know 2 points/ordered pairs
aos, if x incheases while y decreases then slope is negative
when x increases while y increases then slpe if positive
also, if you can convert to y=mx+b, m=slope
another thing if you have ax+by=c then slope=-a/b

so first one
2x-5y=15
a=2
b=-5
-2/-5=2/5
slope=2/5
positive

next
y=-4x
-4 =slope=negative

x increases while y decreases
negative

x increases while y decreases
negative

so
Positive
Negative
Negative
Negative

A. 6x-3y=12
sloope=-6/-3=2

B. y=5x+b
slope=5

C. (8-2)/(3-1)=6/2=3
sloope=3

D. goes up 4 units and goes right 1 unit, 4/1=4
sloope=4

5 is greates
B is the answer

A. (6-3)/(4-3)=3/1=3
slope=3

B. y=4+6x
slope=6

C.12x+6y=18
slope=-12/6=-2

D. goes down 5 units as it goest 1 uniit to right aka -5./1
slope=-5

greatest is 6
B is answer

the starting value I would guess si when x=1 what is the greats y value

look at each
first one
A. x=1 and =-3

B.y=3x-8
y=3(1)-8
y=3-8
y=-5

C. 8x+4y=16
8(1)+4y=16
8+4y=16
4y=8
y=2

D. at 1 unit to right it is 1 nit up so y=1

greatest is 2 or C

so just subsitute 1 for x since x represents how many teaspoons
y=16(1)560
y=16+560
y=576 caloris for 1 sugar teaspoon

for honey, just read off the graph
for when x=1
y=504

so calores of sugar=576
calories in honey=504

ANSWERS

Postive
Negative
Negative
Negative

B

B

C

sugar=576
honey=504

4 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP

dexar [7]

Answer:

A.-4x^2y^4

that the answer

3 0

3 years ago

Triangle A C B is cut by line segment E D. Line segment E D goes from side B C to side A C. The length of B A is 4 x minus 6 and

bezimeni [28]

From the markings on the diagram, we can tell E is the midpoint of BC and <u>D</u> is the midpoint of AC. We can apply the <u>triangle midsegment theorem</u>: ED = ½BA. Substituting in the expressions for the lengths and solving for x, we get x = <u>5</u>. Now, since BE = x, then BC = <u>10</u>.

<h3>What is triangle midpoint theorem?</h3>

Triangle midpoint theorem states that the line segment which joins the midpoints of two (2) sides of a triangle is parallel to the third side, and it's congruent to one-half of the third side.

By applying the triangle midpoint theorem, we can find the value of x:

ED = ½BA

x + 2 = ½(4x - 6)

2x + 4 = 4x - 6

4x - 2x = 6 + 4

2x = 10

x = 10/2

x = 5.

BC = x + x

BC = 5 + 5

BC = 10.

Read more on triangle midpoint theorem here: brainly.com/question/16047906

#SPJ1

6 0

2 years ago

Will mark brainliest for the correct answer!

romanna [79]

Part (a)

Focus on triangle PSQ. We have

angle P = 52

side PQ = 6.8

side SQ = 5.4

Use of the law of sines to determine angle S

sin(S)/PQ = sin(P)/SQ

sin(S)/(6.8) = sin(52)/(5.4)

sin(S) = 6.8*sin(52)/(5.4)

sin(S) = 0.99230983787513

S = arcsin(0.99230983787513)

S = 82.889762826274

Which is approximate

------------

Use this to find angle Q. Again we're only focusing on triangle PSQ.

P+S+Q = 180

Q = 180-P-S

Q = 180-52-82.889762826274

Q = 45.110237173726

Which is also approximate.

A more specific name for this angle is angle PQS, which will be useful later in part (b).

------------

Now find the area of triangle PSQ

area of triangle = 0.5*(side1)*(side2)*sin(included angle)

area of triangle PSQ = 0.5*(PQ)*(SQ)*sin(angle Q)

area of triangle PSQ = 0.5*(6.8)*(5.4)*sin(45.110237173726)

area of triangle PSQ = 13.0074347717966

------------

Next we'll use the fact that RS:SP is 2:1.

This means RS is twice as long as SP. Consequently, this means the area of triangle RSQ is twice that of the area of triangle PSQ. It might help to rotate the diagram so that line PSR is horizontal and Q is above this horizontal line.

We found

area of triangle PSQ = 13.0074347717966

So,

area of triangle RSQ = 2*(area of triangle PSQ)

area of triangle RSQ = 2*13.0074347717966

area of triangle RSQ = 26.0148695435932

------------

We're onto the last step. Add up the smaller triangular areas we found

area of triangle PQR = (area of triangle PSQ)+(area of triangle RSQ)

area of triangle PQR = (13.0074347717966)+(26.0148695435932)

area of triangle PQR = 39.0223043153899

------------

<h3>Answer: 39.0223043153899</h3>

This value is approximate. Round however you need to.

===========================================

Part (b)

Focus on triangle PSQ. Let's find the length of PS.

We'll use the value of angle Q to determine this length.

We'll use the law of sines

sin(Q)/(PS) = sin(P)/(SQ)

sin(45.110237173726)/(PS) = sin(52)/(5.4)

5.4*sin(45.110237173726) = PS*sin(52)

PS = 5.4*sin(45.110237173726)/sin(52)

PS = 4.8549034284642

Because RS is twice as long as PS, we know that

RS = 2*PS = 2*4.8549034284642 = 9.7098068569284

So,

PR = RS+PS

PR = 9.7098068569284 + 4.8549034284642

PR = 14.5647102853927

-------------

Next we use the law of cosines to find RQ

Focus on triangle PQR

c^2 = a^2 + b^2 - 2ab*cos(C)

(RQ)^2 = (PR)^2 + (PQ)^2 - 2(PR)*(PQ)*cos(P)

(RQ)^2 = (14.5647102853927)^2 + (6.8)^2 - 2(14.5647102853927)*(6.8)*cos(52)

(RQ)^2 = 136.420523798282

RQ = sqrt(136.420523798282)

RQ = 11.6799196828694

--------------

We'll use the law of sines to find angle R of triangle PQR

sin(R)/PQ = sin(P)/RQ

sin(R)/6.8 = sin(52)/11.6799196828694

sin(R) = 6.8*sin(52)/11.6799196828694

sin(R) = 0.4587765387107

R = arcsin(0.4587765387107)

R = 27.3081879220073

--------------

This leads to

P+Q+R = 180

Q = 180-P-R

Q = 180-52-27.3081879220073

Q = 100.691812077992

This is the measure of angle PQR

subtract off angle PQS found back in part (a)

angle SQR = (anglePQR) - (anglePQS)

angle SQR = (100.691812077992) - (45.110237173726)

angle SQR = 55.581574904266

--------------

<h3>Answer: 55.581574904266</h3>

This value is approximate. Round however you need to.

8 0

3 years ago

A snail moves 18 millimeters every 24 seconds. What is the snail's rate of speed ?​

A snail moves 18 millimeters every 24 seconds. What is the snail's rate of speed ?