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jeka57 [31]
3 years ago
9

Also need help with this.

Mathematics
2 answers:
stepan [7]3 years ago
8 0
14a -ac = 8w - 6w
a(14-c) = 2w
a= 2w / 14 - c
Fed [463]3 years ago
5 0

Answer:

a = 2w/c/15

Step-by-step explanation:

14a = ac + 2w

ac + 2w + 14a = 0

ac + 14a = -2w

14a + a = -2w/c

15a = 2w/c

a = 2w/c/15

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Halla el conjunto solución del siguiente sistema de ecuaciones aplicando el método de reducción: 2x + 3y = 8 x – 5y = 6
AysviL [449]

Answer:

x = 7.535 and y = 0.307

Step-by-step explanation:

Given that,

Two equations,

2x + 3y = 8 ...(1)

x – 5y = 6....(2)

Multiply equation (2) by -2.

-2x + 10y = -12....(3)

Now, adding equations (1) and (2),

2x + 3y -2x + 10y = 8-12

13y = 4

y = 0.307

Put the value of y in equation (2).

x – 5(0.307) = 6

x = 6 + 1.535

x = 7.535

So, the solutions of the given equation are x = 7.535 and y = 0.307.

4 0
3 years ago
PLEASE HELP DUE IN 30 MINUTES !!!
ad-work [718]

Answer:

C

Step-by-step explanation:

I must be right because the slope is a positive 2 and has a y intercept

3 0
3 years ago
Read 2 more answers
Will give, Branliest.<br><br>Thanks, <br>:) ​
Nikolay [14]

Answer:

250p-195

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
2/10 clear and 18/100 orange. The rest are red and blue. There are 2 more red marbles than blue marbles. What fraction represent
romanna [79]

Answer:

33/100 red, 29/100 blue

Step-by-step explanation:

2/10=20/100

20+18=38

38/100 orange/clear marbles

100-38=62

62 red/blue marbles

62/2=31

31 blue, 31 red

"There are 2 more red marbles than blue marbles."

31-2=29

31+2=33

33/100 red, 29/100 blue.

4 0
3 years ago
Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-ma
pickupchik [31]

Answer:

Answer explained below

Step-by-step explanation:

Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-mails containing the same virus, after which the virus disables itself on that machine. (1) Write a recursive definition (i.e. recurrence relation) to show how many spam emails will be sent out after n seconds. (2) Solve the recurrence relation. (3) How many e-mails are sent at the end of 20 seconds

1.START T=0.....

1000 EMAILS SENT AND RECEIVED BY 1000 M/CS.

T=1.....

EACH OF THE M/C SENDS 10 NEW MAILS ....

.................................

LET M[N] BE THE NUMBER OF MAILS SENT OUT AFTER N SECONDS.

SO , EACH OF THESE M/CS WILL SEND 10 MAILS IN NEXT 1 SECOND.

HENCE NUMBER OF MAILS SENT IN N+1 SECONDS=M[N+1]=

M[N+1]=10*M[N].......................1

THIS IS THE RECURRENCE RELATION.....

2.SOLUTION .....

M[N+1]=10M[N]=10*10M[N-1]=10*10*10M[N-2]=........

M(N+1)=[10^1][M(N)]=[10^2][M(N-1)]=[10^3][M(N-2)]=..........=[10^N][M(1)]=[10^(N+1)][M(0)]

M[N+1]=[10^(N+1)][1000]=[10^(N+1)][10^3]=[10^(N+4)]......................................2

THIS IS THE NUMBER OF MAILS SENT AFTER N+1 SECONDS .....OR ....

M[N]=[10^(N+3)].............................................3

..................IS THE SOLUTION FOR NUMBER OF MAILS SENT AFTER N SECONDS.....

3.AFTER N=20 SECONDS , THE ANSWER IS ....

M[20]=10^(20+3)=10^23

8 0
3 years ago
Read 2 more answers
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