Answer:
$17.65
Step-by-step explanation:
hope this helped!!
Yes, 104.12 is greater than 104.002
because 104.12 rounds up to 104.1
and 104.002 rounds up to 104.0
1. To solve this problem you must sum the volume of the cone and the volume of the hemisphere. This means that the volumen of the prop is:
Vt=Vc+Vh
Vt is the volumen of the prop.
Vc is the volumen of the cone.
Vh is the volume of the hemisphere.
2. The volume of the cone (Vc) is:
Vc=1/3(πr²h)
r=9 in
h=14 in
π=3.14
4. Then, you have:
Vc=(3.14)(9 in)²(14 in)/3
Vc=3560.76 in³/3
Vc=1186.92
5. The volume of the hemisphere (Vh) is:
Vh=2/3(πr³)
π=3.14
r=9 in
6. Then, you have:
Vh=(2)(3.14)(9 in)³/3
Vh=4578.12 in³/3
Vh=1526.04 in³
7. Finally, the volumen of the prop (Vt) is:
Vt=Vc+Vh
Vt=1186.92 in³+1526.04 in³
Vt=2713.0 in³
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What is the volume of the prop?
</span>
The volume of the prop is 2713.0 in³
700.000 = 7 . 10 . 10 . 10 . 10 . 10
We know that equal bases sum the exponents, so,
7 . 10^(1 + 1 + 1 + 1 + 1)
7 . 10^5 = 700.000
But we can also say:
(7 . 10) . 10^4
or
(70 . 10) . 10³
or
(700 . 10) . 10²
or
(7000 . 10) . 10
As we can see, the alternative C shows (7 . 10) . 10^4 which can be a correct ans, so, alternative C.
Answer:
3x3-x2-5x+3
Step-by-step explanation:
Open brackets
