Answer:
Solution in photo
Step-by-step explanation:
This question not incomplete
Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer:
<u>3 5 = 16</u>
<u> 3 = 3 16</u>
<u> 6 = 16</u>
<u> 6 = -4</u>
<u> x = -4/6</u>
each line has the number of boxes to be filled
Answer:
It is given as √288 = √2 × 144. 144 is a perfect square of 12.
You will notice that 48°, x, and x lie upon a straight line. The sum of those angles must then be equal to 180°. Which means:
48+x+x=180
48+2x=180
2x=132
x=66°
