Answer: C
Step-by-step explanation: c is the correct answer. A is incorrect, because 8 is subtracting t, so it is a higher value. B is incorrect because it’s 8/f so 8 is greater. (If it was f/8 then 8 would be less). C is correct because 8 is being taken away from f, not the other way around. And lastly, d is incorrect bc there’s no way to tell which is greater/less. Hope this helped ;)
If we just have
![y = \cos x](https://tex.z-dn.net/?f=y%20%3D%20%5Ccos%20x)
that's an amplitude of 1 and a period of ![2\pi](https://tex.z-dn.net/?f=2%5Cpi)
Let's modify this step by step.
Amplitude of 4. Four times the amplitude means a factor of 4 on the outside.
![y = 4 \cos x](https://tex.z-dn.net/?f=y%20%3D%204%20%5Ccos%20x)
Period of π. Double the period means a factor of 2 on the inside.
![y = 4 \cos(2x)](https://tex.z-dn.net/?f=y%20%3D%204%20%5Ccos%282x%29)
Horizontal shift of π/2 to the left. To the left means adding a positive number to x. The question appear ambiguous. It's not clear to me if we add to x or 2x; let's make it
![y = 4 \cos(2(x + \frac \pi 2))](https://tex.z-dn.net/?f=y%20%3D%204%20%5Ccos%282%28x%20%2B%20%5Cfrac%20%5Cpi%202%29%29)
Vertical shift of 3:
![y = 3 + 4 \cos(2(x + \frac \pi 2))](https://tex.z-dn.net/?f=y%20%3D%203%20%2B%204%20%5Ccos%282%28x%20%2B%20%5Cfrac%20%5Cpi%202%29%29)
![y = 3 + 4 \cos(2x + \pi)](https://tex.z-dn.net/?f=y%20%3D%203%20%2B%204%20%5Ccos%282x%20%2B%20%20%5Cpi%29)
Depending on the interpretation of the phase shift, that pi may be a pi/2.
Answer: ![3 + 4 \cos(2x + \pi)](https://tex.z-dn.net/?f=3%20%2B%204%20%5Ccos%282x%20%2B%20%20%5Cpi%29)
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Answer:
Step-by-step explanation:
perimeter = 36
w = 8
l = 10
Area = 80
Answer: A
Step-by-step explanation: though they did phrase it in a very weird way, and I would suggest to you to make sure your formatting of your question is understandable, A demonstrates distributive property. you can imagine this as two little arrows going from the multiplier outside the parentheses, to each number inside them. this property is used a Lot in basic algebra and using variables. basically, instead of adding inside the parentheses first, and then multiplying that answer by the outside number, you just multiply the outside number by each number inside the parentheses Individually. and then follow through with the operation. this can get confusing if subtraction or negatives are involved, but I'm sure you'll figure it out :)