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Serjik [45]
3 years ago
13

PLEASE HELP!!! Question is above^

Mathematics
1 answer:
julsineya [31]3 years ago
5 0

Answer:

C

Step-by-step explanation:

Calculate the distance (d) using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 9, 2) and (x₂, y₂ ) = (- 4, 2)

d = \sqrt{(-4+9)^2+(2-2)^2}

  = \sqrt{5^2+0^2} = \sqrt{25} = 5 → C

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The position vector for a particle moving on a helix is
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Answer:

a) 25.15

b)

   x = 1

   y = t

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c) (x,y) = (1, -2pi)

Step-by-step explanation:

a)

First lets calculate the velocity, that is, the derivative of c(t) with respect to t:

v(t) = (-sin(t), cos(t), 2t)

The velocity at t0=4pi is:

v(4pi) = (0, 1, 8pi)

And the speed will be:

s(4pi) = √(0^2+1^2+ (8pi)^2) = 25.15

b)

The tangent line to c(t) at t0 = 4pi has the parametric form:

(x,y,z) = c(4pi) + t*v(4pi)

Since

 c(4pi) = (1, 0, (4pi)^2)

The tangent curve has the following components:

x = 1

y = t

z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)

c)

The intersection with the xy plane will occurr when z = 0

This happens at:

  t1 = -2pi

Therefore, the intersection will occur at:

(x,y) = (1, -2pi)

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What is the simplified from of 4x^2-25 over 2x-5?
stealth61 [152]
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