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3 years ago

Please help !!!! picture shown

Mathematics

2 answers:

Drupady [299]3 years ago

7 0

My best bet would be C.

Serhud [2]3 years ago

4 0

$\sqrt{10 x^{2} }$ · $\sqrt{5x}$ = $\sqrt{50 x^{3} }$ . This can be simplified to 5x $\sqrt{2x}$ , because √50 simplifies to 5√2 (since 5x5x2 equals 50) and the square root sign takes x² from x³ and turns it into just x.

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Tim wants to boil rice on the stove. He needs to use exactly three gallons of water in a pot to boil the rice. Which method shou

Volgvan

B. is the answer because he can just refill the 1 gallon jug to eventually measure out 3 gallons!

7 0

3 years ago

Read 2 more answers

How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x

Fofino [41]

Answer:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

Step-by-step explanation:

We are given the function:

$f(x)=-4x^5-8x^3+12x$

And we want to finds its zeros.

Therefore:

$0=-4x^5-8x^3+12x$

Firstly, we can divide everything by -4:

$0=x^5+2x^3-3x$

Factor out an x:

$0=x(x^4+2x^2-3)$

This is in quadratic form. For simplicity, we can let:

$u=x^2$

Then by substitution:

$0=x(u^2+2u-3)$

Factor:

$0=x(u+3)(u-1)$

Substitute back:

$0=x(x^2+3)(x^2-1)$

By the Zero Product Property:

$x=0\text{ and } x^2+3=0\text{ and } x^2-1=0$

Solving for each case:

$x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}$

Therefore, our real and complex zeros are:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

4 0

3 years ago

-2x + 15y = -24<br><br>2x + 9y = 24<br>

pashok25 [27]

Answer:

dont know

Step-by-step explanation:

sorry

3 0

3 years ago

Round your answer to two decimal places log 6e

Andru [333]

Solution: We know that e is numerical constant and is equal to 2.71828.

Therefore log( 6 x 2.71828) = 1.21

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3 years ago

Will the opposite of a number always sometimes or never be greater than the number itself

stealth61 [152]

Sometimes, because if the number is negative, the opposite is greater, but if the number is positive, the opposite is smaller.

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3 years ago