Answer:
The answer is 18p^3r and 63p^3
Step-by-step explanation:
G.C.F of 18p^3 r and 45p^4q is = 9p^3
18p^3r = 2*3*3*p*p*p*r
45p^4q = 3*3*5*p*p*p*q
Thus the G.C.F is 3*3*p*p*p = 9p^3
G.C.F of 63p^3 and 45p^4q is = 9p^3
63p^3 = 3*3*7*p*p*p
45p^4q = 3*3*5*p*p*p*q
Thus the G.C.F is 3*3*p*p*p = 9p^3
Therefore the answer is 18p^3r and 63p^3....
Subtract -6 on both sides
Now you have x/-2 on the left and 3 on the right
Then multiply -2 on both sides, leaving you with x on the left and -6 on the right
So x< -6
I think you meant to say

(as opposed to <em>x</em> approaching 2)
Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:

Since opposite angles of a cyclic quadrilateral are supplementary,
A= 180-101=79°
B= 180-68=112°
Answer:
I just learned about this, and if its wrong i am so so sorry
Step-by-step explanation:
a= 120
b= 60
w= 120
x= 120
r= 105
q= 105
p= 105