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Anastasy [175]
3 years ago
6

Which number is a rational number and an integer? PLS ANSWER

Mathematics
2 answers:
ycow [4]3 years ago
8 0

Answer:

d is the correct answer, others aren't correct

notsponge [240]3 years ago
8 0
The answer is -15
hope this helped
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What is 3,125 divided by 200 as a decimal?
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Answer:

15.625

Step-by-step explanation:

3,125/200 = 15.625

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Given an int variable n that has been initialized to a positive value and, in addition, int variables k and total that have alre
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Answer:

total = 0;

for (k = 0; k <= n; k++)

total += Math.pow(k,3);

Step-by-step explanation:

Here the variable total is declared and initialized with a value zero  

Then a for loop is defined with a counter k whose initial value is set to zero then a condition for the loop is that the counter k does not exceed n k<=n and then within the loop a statement which add the cube of the counter k to the variable total and still assigns it to the variable total is defined

  total += Math.pow(k,3);

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50 POINTS 10 QUESTIONS! <br><br> Solve each quadratic equation using factoring<br><br> PLEASE HELP!!
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Answer:

Quadratic Equation | Factoring

Solve each quadratic equation using factoring.

1) v² + 5v + 6 = 0

doing middle term factorisation

v²+(3+2)v+6=0

v²+3v+2v+6=0

v(v+3)+2(v+3)=0

(v+3)(v+2)=0

either

<u>v=-3</u>

<u>or</u>

<u>v=-2</u>

2) g² - 3g = 4

keeping all terms in one side

g²-3g-4=0

doing middle term factorisation

g²-(4-1)g-4=0

g²-4g+g-4=0

g(g-4)+1(g-4)=0

(g-4)(g+1)=0

either

<u>g=4</u>

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<u>g=-1</u>

3)w² + 4w = 0

w(w+4)=0

either

<u>w=0</u>

<u>or</u>

<u>w=-4</u>

4) s² - 8s + 12 = 0

doing middle term factorisation

s²-(6+2)+12=0

s²-6s-2s+12=0

s(s-6)-2(s-6)=0

(s-6)(s-2)=0

either

<u>s=6</u>

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<u>s=2</u>

5) x ²+ 2x - 35 = 0

doing middle term factorisation

x²+(7-5)x-35=0

x²+7x-5x-35=0

x(x+7)-5(x+7)=0

(x+7)(x-5)=0

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<u>x=-7</u>

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6) r(r + 2) = 99

opening bracket

r²+2r=99

keeping all terms in one side

r²+2r-99=0

r²+(11-9)r-99=0

r²+11r-9r-99=0

r(r+11)-9(r+11)=0

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7)k(k-4)=-3

opening bracket

k²-4k=-3

keeping all terms in one side

k²-4k+3=0

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8)t²+ 3t + 2 = 0

doing middle term factorisation

t²+(2+1)t+2=0

t²+2t+t+2=0

t(t+2)+1(t+2)=0

(t+2)(t+1)=0

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9)m ^ 2 - 81 = 0

m²=81

doing square root in both side

\sqrt{m²}=\sqrt{9²}

<u>m=±9</u>

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<u>m</u><u>=</u><u>9</u>

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doing middle term factorisation

h²-(10+7)h+70=0

h²-10h-7h+70=0

h(h-10)-7(h-10)=0

(h-10)(h-7)=0

either

<u>h</u><u>=</u><u>1</u><u>0</u>

<u>or</u>

<u>h</u><u>=</u><u>7</u>

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