Using the triangle of pascal we have that the expression equivalent to (x + y) ^ 6 is given by:
x ^ 6 + 6x ^ 5y + 15x ^ 4y ^ 2 + 20x ^ 3y ^ 3 + 15x ^ 2y ^ 4 + 6xy ^ 5 + y ^ 6
Therefore, the coefficients of the expansion are given by:
1, 6, 15, 20, 15, 6, 1
Answer:
The coefficients corresponding to k = 0, 1, 2, ..., 6 in the expansion of (x + y) ^ 6 are 1, 6, 15, 20, 15, 6, 1
Answer:4(2x + 1) = 12x + 3 - 4x +1=0
Step-by-step explanation:
group like terms =4(2x+1)=12x-4x+3+1
add similar elements=4(2x+1)=8x+3+1
add the numbers=4(2x+1)=8x+4
expand=8x+4=8x+4
subtract 4 from both sides 8x+4-4=8x+4-4
simplify=8x=8x
subtract 8x both sides=0
Answer:
units
Step-by-step explanation:
Given
Shape: Kite WXYZ
W (-3, 3), X (2, 3),
Y (4, -4), Z (-3, -2)
Required
Determine perimeter of the kite
First, we need to determine lengths of sides WX, XY, YZ and ZW using distance formula;

For WX:





For XY:






For YZ:






For ZW:







The Perimeter (P) is as follows:



units
Answer:
CORRECT OPTION is (C) The flight will be late on one of the three days.
Step-by-step explanation:
The 7am flight from Dallas to Chicago is on time 75% of the time.
A spinner with four sections was created by Fran to simulate this scenario.
Since the 4 sections were equal, it means each section was 25% of the spinner.
3 sections were shaded. That implies 25 × 3 = 75% of the spinner was shaded area.
This coincides with the 75% probability that the flight is on time on a given day.
In other words, if the spinner's pointer lands on shaded area, the flight will be on time. If the pointer lands on an unshaded portion, the flight will be late.
Now Fran spun the spinner 3 times so she has 3 outcomes. The outcomes are:
- Shaded - Shaded - Unshaded
CORRECT OPTION is (C) The flight will be late on one of the three days.