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mamaluj [8]
2 years ago
9

If you get the answers right you will get brainliest and get a thanks :-)

Mathematics
1 answer:
sergejj [24]2 years ago
5 0
5.   3, 12, 48, 192, 768, ...

You can find the 15th term by using the formula a_n = a_1 *r^{n-1}, where a_1 is the first term of the sequence, r is the common ratio, and n is the number of the term you want to find.

<span>a_n = a_1 *r^{n-1}   Plug in your information (the common ration is x4)
</span>a_{15} = 3 * 4^{14}   Simplify the exponent
a_{15} = 3 * 268435456   Multiply
a_{15} = 805306368

The 15th term of the sequence is <span>805306368.

6.   200, 40, 8, 1.6, ...
Using guess and check, I found that the pattern here is </span>÷5, ÷5, ÷5, .... That can also be written as ×\frac{1}{5}, ×\frac{1}{5}, <span>×\frac{1}{5}, ... When you are multiplying the terms of a sequence, that is a geometric sequence.
</span>
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Jacob is working two summer jobs, making $11 per hour babysitting and making $24
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Answer:

answer key:$11:$24:$120

Step-by-step explanation:

<h2>*answers*</h2><h2>tysm for points hehehe</h2>
6 0
2 years ago
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In the diagram below, AngleDAB and AngleDAC are adjacent angles. Lines A B, A D, and A C create two angle. The space between lin
iren [92.7K]

Answer:

  ∠DAB = 80°

  ∠BAC = 105°

Step-by-step explanation:

You are given ...

  ∠DAC = 25° = (x -20)°

Adding 20°, we have ...

  x° = 45°

Then the measures of the other angles are ...

  ∠DAB = (2x -10)° = 2(45°) -10°

  ∠DAB = 80°

and

  ∠BAC = ∠DAB +∠DAC = 80° +25°

  ∠BAC = 105°

_____

Nothing in this problem statement defines a circle.

3 0
3 years ago
In a class 27 of students, 12 have a cat and 11 have a dog. There are 5 students who have a cat and a dog. What is the probabili
frosja888 [35]

Answer:

41.67% probability that a student has a dog given that they have a cat

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: having a cat.

Event B: having a dog.

12 of 27 students have a cat:

This means that P(A) = \frac{12}{27}

5 students who have a cat and a dog.

This means that P(A \cap B) = \frac{5}{27}

What is the probability that a student has a dog given that they have a cat?

P(B|A) = \frac{\frac{5}{27}}{\frac{12}{27}} = \frac{5}{12} = 0.4167

41.67% probability that a student has a dog given that they have a cat

6 0
3 years ago
Charlotte runs a farm stand that sells bananas and raspberries. Each pound of bananas sells for $3.25 and each pound of raspberr
Salsk061 [2.6K]

Answer:

50 pounds of bananas

37 pounds of raspberries

Step-by-step explanation:

3.25(b) + 1.75(b - 13) = 227.25

5b - 22.75 = 227.25

5b = 250

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b - 13 = 37

4 0
3 years ago
A zookeeper predicted that the weight of a newborn lion would be 2.8 pounds. when the zoo's lion gave birth, the newborn weighed
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Answer:

20%

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