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Mathematics

1 answer:

sergejj [24]2 years ago

5 0

5. 3, 12, 48, 192, 768, ...

You can find the 15th term by using the formula $a_n = a_1 *r^{n-1}$ , where $a_1$ is the first term of the sequence, r is the common ratio, and n is the number of the term you want to find.

<span> $a_n = a_1 *r^{n-1}$ Plug in your information (the common ration is x4)
</span> $a_{15} = 3 * 4^{14}$ Simplify the exponent
$a_{15} = 3 * 268435456$ Multiply
$a_{15} = 805306368$

The 15th term of the sequence is <span>805306368.

6. 200, 40, 8, 1.6, ...
Using guess and check, I found that the pattern here is </span>÷5, ÷5, ÷5, .... That can also be written as × $\frac{1}{5}$ , × $\frac{1}{5}$ , <span>× $\frac{1}{5}$ , ... When you are multiplying the terms of a sequence, that is a geometric sequence.
</span>

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Limx→+∞ (x-(lnx)^2) =?

expeople1 [14]

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Hope this helps.

3 0

3 years ago

il63 [147K]

The required value after simplification of the s = -16/3. None of these are correct.

Given that,
To simplify $[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2$ and to find the value of s in $x^s$ .

<h3>What is simplification?</h3>

The process in mathematics to operate and interpret the function to make the function simple or more understandable is called simplifying and the process is called simplification.

Simplification,

$=[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2\\= \frac{x^{4/3}x^{-1}}{x^2x^3*{x}^{2/3}}\\= \frac{x^{1/3}}{x^{17/3}}\\=x^{-16/3}$
Comparing with $x^S$
s = -16/3