Please do this fast. Put 6/3 6/2 and 6/8 LEAST TO GREATEST. FASSSSSTTTTTTTT!!!

in chicago il the average wind speed is 10.4 miles per hour in great falls mt the average wind speed is 13.1 miles per hour how

Anika [276]

The difference between the two wind speeds is 2.7. If you use subtraction, you'll see the answer. Hope this helps!

Aye Sir!

4 0

3 years ago

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The TV you want costs $650. You have $410 now and plan

Anvisha [2.4K]

Answer:

5 months

Step-by-step explanation:

Save every month to earn up to all the money to buy the Tv it will take about 5 months to earn the money and buy it

Hope this help you!

8 0

3 years ago

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Twice Use what you have learned to compare circles by their characteristics. 1. Draw each circle. A. Radius length of 3 centimet

Gwar [14]

Answer:

1. a. Please find attached, the diagram for the first circle with radius = 3 cm

b. Please find attached, the diagram for the second circle with diameter = 3 cm

2. The similarities are;

a) Both circles can be described by a point and a radius or a diameter

The differences are;

a) The length of the radiuses are different for the two circles (3 cm and 1.5 cm)

b) The circumferences of the two circles are different

c) The area covered by the two circles are different

3. The circumference of the circle with radius equal to 3 cm is larger than the circumference of the circle with diameter equal to 3 cm

4. The circumference to diameter ratio of the circle with radius = 3 cm is π

The circumference to diameter ratio of the circle with diameter = 3 cm is π

Both circles have equal circumference to diameter ratio given that the circumference = π × The diameter

Step-by-step explanation:

1. a. The radius length of the first circle = 3 cm

The diagram for the first circle with radius 3 cm is attached

b. The diameter length of the second circle = 3 cm

The diagram for the second circle with diameter 3 cm is attached

2. The similarities are;

a) Both circles can be described by a point and a radius or a diameter

The differences are;

a) The length of the radiuses are different for the two circles (3 cm and 1.5 cm)

b) The circumferences of the two circles are different

c) The area covered by the two circles are different

3. The circumference of the circle with radius equal to 3 cm is 2 × π × 3 = 6·π cm

The circumference of the circle with diameter equal to 3 cm is π × 3 = 3·π cm

Therefore, the circumference of the circle with radius equal to 3 cm is larger than the circumference of the circle with diameter equal to 3 cm

4. The circumference to diameter ratio of the circle with radius = 3 cm is 6·π cm/(2 × 3 cm) = π

The circumference to diameter ratio of the circle with diameter = 3 cm is 3·π cm/(3 cm) = π.

Both circles have equal circumference to diameter ratio given that the circumference = π × The diameter.

7 0

3 years ago

Given this quadratic equation, 2x^2-x-28=0,

Olegator [25]

Step-by-step explanation:

how to help people that helps

3 0

3 years ago

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Exercise 3.7.4: let a = 2 1 0 0 2 0 0 0 2 .

swat32

With

$\mathbf A=\begin{bmatrix}2&1&0\\0&2&0\\0&0&2\end{bmatrix}$

we have

$\det(\mathbf A-\lambda\mathbf I)=\begin{vmatrix}2-\lambda&1&0\\0&2-\lambda&0\\0&0&2-\lambda\end{vmatrix}=(2-\lambda)^3$

so $\mathbf A$ has one eigenvalue, $\lambda=2$ , with multiplicity 3.

In order for $\mathbf A$ to not be defective, we need the dimension of the eigenspace to match the multiplicity of the repeated eigenvalue 2. But $\mathbf A-2\mathbf I$ has nullspace of dimension 2, since

$\begin{bmatrix}0&1&0\\0&0&0\\0&0&0\end{bmatrix}\begin{bmatrix}x\\y\\z\end{bmatrix}=\mathbf 0\implies x=0\text{ or }y=0$

That is, we can only obtain 2 eigenvectors,

$\begin{bmatrix}1\\0\\0\end{bmatrix}\text{ and }\begin{bmatrix}0\\0\\1\end{bmatrix}$

and there is no other. We needed 3 in order to complete the basis of eigenvectors.

3 0

3 years ago