Answer:
Step-by-step explanation:
The total amount paid by a member according to this table is
Total Amount Paid = fee + monthly fee(# of months)
Since the fee is the same regardless of how many months one signs up for, it should come out the same for each row in our table.
Row 1:
TAP = fee + 15(#months)
135 = fee + 15(4) and
135 = fee + 60 so
fee = $75
Row 2:
165 = fee + 15(6) and
165 = fee + 90 so
fee = $75
Row 3:
255 = fee + 15(12) and
255 = fee + 180 so
fee = $75
Apparently, the fee is $75.
Answer:
See Explanation
Step-by-step explanation:
The question is incomplete, as Hernando and Rachel's solution are not provided. So, I will just solve the question directly.
Given

Required
Factor

Group into 2
![2mp-6p+27-9m = [2mp-6p]+[27-9m]](https://tex.z-dn.net/?f=2mp-6p%2B27-9m%20%3D%20%5B2mp-6p%5D%2B%5B27-9m%5D)
Factor each group
![2mp-6p+27-9m = 2p[m-3]+9[3-m]](https://tex.z-dn.net/?f=2mp-6p%2B27-9m%20%3D%202p%5Bm-3%5D%2B9%5B3-m%5D)
Rewrite 3 - m as -(m-3)
So, we have:
![2mp-6p+27-9m = 2p[m-3]-9[m-3]](https://tex.z-dn.net/?f=2mp-6p%2B27-9m%20%3D%202p%5Bm-3%5D-9%5Bm-3%5D)
Factor out m - 3
![2mp-6p+27-9m = [2p-9][m-3]](https://tex.z-dn.net/?f=2mp-6p%2B27-9m%20%3D%20%5B2p-9%5D%5Bm-3%5D)
9514 1404 393
Answer:
A ≈ 65.4°
Step-by-step explanation:
The mnemonic SOH CAH TOA is intended to remind you of the trig relations associated with pairs of sides. For angle A, given sides b and c are the adjacent side and the hypotenuse, respectively. The appropriate relation is ...
Cos = Adjacent/Hypotenuse
cos(A) = b/c
A = arccos(b/c) = arccos(2.5/6)
A ≈ 65.4°
Answer:
Its D. -14
Step-by-step explanation:
Answer:
the selling price of the goods is ₹6,00,000
Step-by-step explanation:
The computation of the selling price of the goods are shown below:
As we know that
Selling price = Cost price + profit
= 5,00,000 + 5,00,000 × 0.20
= 5,00,000 + 1,00,000
= ₹6,00,000
Hence, the selling price of the goods is ₹6,00,000