Answer:
4x/y¹¹
Step-by-step explanation:
1) take out constants
40/10 * x⁻⁴y⁻⁶/x⁻⁵y⁵
2) simplify 40/10 to 4
4 * x⁻⁴y⁻⁶/x⁻⁵y⁵
3) Use Quotient Rule: xᵃ/xᵇ=xᵃ⁻ᵇ
4x⁻⁴⁺⁵y⁻⁶⁻⁵
4) Simplify -4 + 5 to 1
4x¹y⁻⁶⁻⁵
5) simplify -6-5 to -11
4x¹y⁻¹¹
6) use rule of one: ₓ¹=ₓ
4xy⁻¹¹
7) use negative power rule: x⁻ᵃ=1/xᵃ
4x * 1/y¹¹
8) simplify
4x/y¹¹
Answer:
The second one:
L∪J={i,j,k,l,m,n,o}
Step-by-step explanation:
The union is the elements listed in either set.
So since l,m,n, and o are elements of set L, they will also be elements of whatever it is "unioned" with.
Since i,j,k,l and m are elements of set J, they will also be elements of whatever it is "unioned" with.
When you write the union, just be sure to include each element that occurs in either set once.
So the union of L and J is {i,j,k,l,m,n,o}.
The answer is the second one.
The intersection would actually be that upside down U thing, the ∩ symbol. The intersection of two sets is a list of elements that both sets include. So here the intersection would just consist of the elements l amd m.
<span>B:she could divided both sides by 3 to get x+2=2y</span>
Answer:
a
Step-by-step explanation:
it's non-linear
