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irga5000 [103]
3 years ago
7

I need help with this, if anyone can I appreciate it. ✨

Mathematics
2 answers:
ipn [44]3 years ago
8 0

Answer:

85, -91

Step-by-step explanation:

Pavlova-9 [17]3 years ago
3 0
85, 91 is the answer
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Solve x+5y=11 and -x+4y=7 using elimination​
ddd [48]

Answer: (1, 2)

Concept:

There are three general ways to solve systems of equations:

  1. Elimination
  2. Substitution
  3. Graphing

Since the question has specific requirements, we are going to use <u>elimination</u>

Solve:

<u>Given expressions</u>

x + 5y = 11

-x + 4y = 7

<u>Add both equations together to elimination [x] variable</u>

(x + 5y) + (-x + 4y) = 11 + 7

x - x + 5y + 4y = 18

9y = 18

<u>Divide 9 on both sides</u>

9y / 9 = 18 / 9

\boxed{y=2}

<u>Find the x value</u>

x + 5y = 11 ⇔ <em>Given equation</em>

x + 5(2) = 11 ⇔ <em>Substitute values of y</em>

x + 10 = 11 ⇔ <em>Simplify by multiplication</em>

x + 10 - 10 = 11 - 10 ⇔ <em>Subtract 10 on both sides</em>

\boxed{x=1}

Hope this helps!! :)

Please let me know if you have any questions

5 0
3 years ago
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Find the area of a regular hexagon with the given measurement.
yawa3891 [41]

Answer:  24\sqrt{3}in^2 or  41.56in^2

Step-by-step explanation:

You can find the area of a regular hexagon with the following formula:

A_{(hexagon)}=\frac{3\sqrt{3}s^2}{2}

Where "s" is any side of the regular hexagon.

For this hexagon you know that the length of each side is 4 inches. Then, you must substitute s=4in into the formula  A_{(hexagon)}=\frac{3\sqrt{3}s^2}{2}.

Therefore, the area of this regular hexagon is:

 A_{(hexagon)}=\frac{3\sqrt{3}(4in)^2}{2}

 A_{(hexagon)}=24\sqrt{3}in^2 or A_{(hexagon)}=41.56in^2

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3 years ago
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Given a cone with a volume of 288 in and height 7 in find the base radius of the cone
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Which figure is a convex polygon?
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A.

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Convex polygon

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