From the information given, the tins are circular /cylindrical because they have a diameter.
So we need to find out the base area of each tin .
Base Area = π r²
radius here will be 25/2 = 12.5
Area = 3.14 × 12.5 ×12.5
Area = 490.6cm²
For the tray the dimensions are 600mm and 500mm which seem to allude the trays are of a regular shape such as a rectangle. Let us assume it is so.
600mm = 60cm, and 500mm = 50cm
Area = L × w
Area = 50 × 60 = 3000cm²
Each tray will fit 3000 ÷ 490.6 = 6.1
6 cake tins will fit into one tray
To solve correctly, graph both inequalities. The solution is where they overlap. <em>See attachment for graph. </em>Which coordinate is plotted in the overlapping section?
If you don't have the tools to graph them, then plug each coordinate into both inequalities. The coordinate that makes a true statement for BOTH inequalities, is the answer.
(0, 4): 4 > -2 TRUE 0 + 4 < 4 FALSE
(-3, 5): 5 > -2 TRUE -3 + 5 < 4 TRUE THIS IS THE ANSWER!
(1, 4): 4 > -2 TRUE 1 + 4 < 4 FALSE
(-2, -3): -3 > -2 FALSE
Answer: (-3, 5)
Answer:
Promedio de kg por arbol= 28.35kg
Step-by-step explanation:
Dada la siguiente información:
Cantidad de árboles= 648
Cantidad total de kg= 18.367,42 kg
<u>Para calcular el promedio de kg por arbol, tenemos que usar la siguiente formula:</u>
<u></u>
Promedio de kg por arbol= cantidad total de kg / número de arboles
Promedio de kg por arbol= 18.367,42 / 648
Promedio de kg por arbol= 28.35kg
How fast the volume of the sphere is changing when the surface area is 10 square centimeters is it is increasing at a rate of 30 cm³/s.
To solve the question, we need to know the volume of a sphere
<h3>
Volume of a sphere</h3>
The volume of a sphere V = 4πr³/3 where r = radius of sphere.
<h3>How fast the volume of the sphere is changing</h3>
To find the how fast the volume of the sphere is changing, we find rate of change of volume of the sphere. Thus, we differentiate its volume with respect to time.
So, dV/dt = d(4πr³/3)/dt
= d(4πr³/3)/dr × dr/dt
= 4πr²dr/dt where
- dr/dt = rate of change of radius of sphere and
- 4πr² = surface area of sphere
Given that
- dr/dt = + 3 cm/s (positive since it is increasing) and
- 4πr² = surface area of sphere = 10 cm²,
Substituting the values of the variables into the equation, we have
dV/dt = 4πr²dr/dt
dV/dt = 10 cm² × 3 cm/s
dV/dt = 30 cm³/s
So, how fast the volume of the sphere is changing when the surface area is 10 square centimeters is it is increasing at a rate of 30 cm³/s.
Learn more about how fast volume of sphere is changing here:
brainly.com/question/25814490
M∠LON=77 ∘ m, angle, L, O, N, equals, 77, degrees \qquad m \angle LOM = 9x + 44^\circm∠LOM=9x+44 ∘ m, angle, L, O, M, equals, 9,
timama [110]
Answer:
Step-by-step explanation:
Given
<LON = 77°
<LOM = (9x+44)°
<MON = (6x+3)°
The addition postulate is true for the given angles since tey have a common point O:
<LON = <LOM+<MON
Since we are not told what to find we can as well look for the value of x, <LOM and <MON
Substitute the given parameters and get x
77 = 9x+44+6x+3
77 = 15x+47
77-47 = 15x
30 = 15x
x = 30/15
x = 2
Get <LOM:
<LOM = 9x+44
<LOM = 9(2)+44
<LOM = 18+44
<LOM = 62°
Get <MON:
<MON = 6x+3
<MON = 6(2)+3
<MON = 12+3
<MON = 15°
