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3 years ago

11

On your last math test you earned an 88%. Of the 26 questions on the test, how many did you get correct?

2 answers:

creativ13 [48]3 years ago

8 0

Multiply total number of questions on the test by the percent:

26 x 0.88 = 22.88

Round to the nearest whole number:

22.88 = 23

You got 23 questions correct.

dybincka [34]3 years ago

7 0

Answer:

i belive the answer is 23

Step-by-step explanation:

You just have to divide then multiple by 100

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HELP ASAPPPP PLEASE

Lerok [7]

Answer:

I don't know but i think the answer is:

3/8 and 1/2

Step-by-step explanation:

add both and the answer is there

3 0

2 years ago

Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

Ugo [173]

Answer:

$Side\ B = 6.0$

$\alpha = 56.3$

$\theta = 93.7$

Step-by-step explanation:

Given

Let the three sides be represented with A, B, C

Let the angles be represented with $\alpha, \beta, \theta$

[See Attachment for Triangle]

$A = 10cm$

$C = 12cm$

$\beta = 30$

What the question is to calculate the third length (Side B) and the other 2 angles ( $\alpha\ and\ \theta$ )

Solving for Side B;

When two angles of a triangle are known, the third side is calculated as thus;

$B^2 = A^2 + C^2 - 2ABCos\beta$

Substitute: $A = 10$ , $C =12$ ; $\beta = 30$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30$

$B^2 = 100 + 144 - 240*0.86602540378$

$B^2 = 100 + 144 - 207.846096907$

$B^2 = 36.153903093$

Take Square root of both sides

$\sqrt{B^2} = \sqrt{36.153903093}$

$B = \sqrt{36.153903093}$

$B = 6.0128115797$

$B = 6.0$ <em>(Approximated)</em>

Calculating Angle $\alpha$

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute: $A = 10$ , $C =12$ ; $B = 6$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 180 - 144 *Cos\alpha$

Subtract 180 from both sides

$100 - 180 = 180 - 180 - 144 *Cos\alpha$

$-80 = - 144 *Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}$

$\frac{-80}{-144} = Cos\alpha$

$0.5555556 = Cos\alpha$

Take arccos of both sides

$Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)$

$Cos^{-1}(0.5555556) = \alpha$

$56.25098078 = \alpha$

$\alpha = 56.3$ <em>(Approximated)</em>

Calculating $\theta$

Sum of angles in a triangle = 180

Hence;

$\alpha + \beta + \theta = 180$

$30 + 56.3 + \theta = 180$

$86.3 + \theta = 180$

Make $\theta$ the subject of formula

$\theta = 180 - 86.3$

$\theta = 93.7$

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3 years ago

Need help with 9-12 plzzzzz

Vladimir79 [104]

Hi Lexia it's Aliyah

4 0

3 years ago

Read 2 more answers

Karim says the ratio of the distance he ran to the distance Shawn ran 4:3 give three possibilities for the distance each could h

jok3333 [9.3K]

Karim=4,8km,12km,16km Shawn=3,6km,9km,12km

4 0

3 years ago

ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing. Show your work or give an explaination.

pentagon [3]

Answer:

D. $f(x)=4x^{2}+1$

Step-by-step explanation:

There is a translation 1 point up along the y axis and a compression of 4.

Moving a function up (let's use <em>h</em> for the amount of points up) would change the function as so:

$f(x)=x^{2} +h$

Meanwhile, the compression would modify x in this case. You can eliminate any answers (A. and B.) that have no modification to x, and eliminate C., as a fraction modification would actually widen the graph instead of compress it.

Hope this helps! :]

4 0

2 years ago