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Helen [10]
3 years ago
5

A math club has 24 members at the beginning of the school year. Four more people

Mathematics
1 answer:
azamat3 years ago
7 0

Answer:

B)  Domain T (x)=1/x = 1/32 =32     Range = 6

Step-by-step explanation:

B) The domain of a function is the complete set of possible values of the independent variable. In plain English, this definition means: The domain is the set of all possible x-values which will make the function "work", and will output real y-values

Range is 32 amount of total pupils deducted by 24 smallest number

C) T (m) =OO+0=0  = T(m) =24+20=44

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Jamie put 8 squares together to make a rectangle. There are 2 rows of squares. Each row has 4 squares. How many pairs of sides t
Ludmilka [50]
10 pairs of sides (see the picture attached)

3 0
3 years ago
How would adding a score of 0 to this data affect the mean and median game scores? 100,120,130,150
ivanzaharov [21]

Answer:

Step-by-step explanation:

It would add a 0

8 0
3 years ago
It’s my last question :(
jenyasd209 [6]

Answer:

Perimeter =  28·√2 + 24 feet

Step-by-step explanation:

The dimensions of the initial sheet of plywood are;

The length of the sheet of plywood = 25 ft.

The width of the sheet of plywood = 14 ft.

The shape cut from each corner of the sheet of plywood  = A right triangle

The leg length of each of the cut out right triangles = 7 ft.

The number of leg lengths of the right triangle cut from the length side of the initial sheet of plywood = 2

The length of the parallel sides of the remaining hexagonal piece of plywood = Initial length of the plywood - 2 × The leg length of the cut out right triangle

∴ The length of the parallel sides of the remaining hexagonal piece of plywood = 26 ft. - 2 × 7 ft.  = 12 ft.

The other side length of the remaining hexagonal piece of plywood = The hypotenuse side of the cut out right triangle

The hypotenuse side of the cut out right triangle = √((7 ft.)² + (7 ft.)²) = 7·√2 ft.

∴ The other side length of the remaining hexagonal piece of plywood = 7·√2

The number of side lengths in the remaining hexagonal piece of plywood = 4

The perimeter of the remaining hexagonal piece of plywood = 2 × The length of the parallel sides + 4 × The other side lengths

∴ The perimeter of the remaining hexagonal piece of plywood = 2 × 12 ft. + 4 × 7·√2 = (28·√2 + 24) ft.

The perimeter of the remaining hexagonal piece of plywood = (28·√2 + 24) feet

6 0
3 years ago
Does anyone knows how to do that? <br> I need to solve for x
vesna_86 [32]

Answer:

x=17°

Step-by-step explanation:

Because the diagonal lines are marked with arrows, we know that they are parallel. The two angles that are marked with measures are same-side interior angles. Same-side interior angles of parallel lines are supplementary, meaning that the sum of their measures is 180°.

Now, with all of this information, we can set up the following equation and solve for x:

115+4x-3=180

112+4x=180 (Simplify LHS by combining like terms)

112+4x-112=180-112 (Subtract 112 from both sides of the equation to isolate x)

4x=68 (Simplify)

\frac{4x}{4}=\frac{68}{4} (Divide both sides of the equation by 4 to get rid of x's coefficient)

x=17° (Simplify)

Hope this helps!

5 0
3 years ago
Rachel is collecting donations for the local animal shelter. So far she has collected $245, which is 70% of what she hopes to co
Nata [24]

Answer:

The money Rachael plan to collect for the shelter is <u>$350</u>.

Step-by-step explanation:

Given:

Rachel is collecting donations for the local animal shelter.

So far she has collected $245, which is 70% of what she hopes to collect.

Now, to find the money Rachael plan to collect for the shelter.

Let the total amount Rachael plan to collect be x.

Amount she collected = $245.

Percentage of amount she collected = 70%.

Now, to get the amount Rachael plan to collect we put an equation:

70\%\ of\ x=\$245.

⇒ \frac{70}{100} \times x=245

⇒ 0.70\times x=245

⇒ 0.70x=245

<em>Dividing both sides by 0.70 we get:</em>

⇒ x=\$350.

Therefore, the money Rachael plan to collect for the shelter is $350.

4 0
3 years ago
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