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elena55 [62]
3 years ago
6

HELP ME ASAP! PLS!!!!

Mathematics
2 answers:
IrinaK [193]3 years ago
6 0

Answer:

B

Step-by-step explanation:

mylen [45]3 years ago
5 0

Answer:

(B) A right triangle with side length of StartRoot 47 EndRoot and hypotenuse of 10

Step-by-step explanation:

I just took the quiz on edge

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Are squaring a number and taking a root ___ operations.<br><br>the same<br>opposite<br>different​
Ber [7]
They are opposite operations
4 0
3 years ago
You are designing a rectangular garden. the garden will be enclosed by fencing on three sides and by a house on the fourth side.
RUDIKE [14]
Suppose the dimensions of the rectangle is x by y and let the side enclosed by a house be one of the sides measuring x, then the sides that is to be enclosed are two sides measuring y and one side measuring x.

Thus, the length of fencing needed is given by

P = x + 2y

The area of the rectangle is given by xy,

i.e.

xy = 288  \\  \\  \\  \\ \Rightarrow y= \frac{288}{x}

Substituting for y into the equation for the length of fencing needed, we have

P=x+2\left( \frac{288}{x} \right)=x+ \frac{576}{x}

For the amount of fencing to be minimum, then

\frac{dP}{dx} =0 \\  \\ \Rightarrow1- \frac{576}{x^2} =0 \\  \\ \Rightarrow \frac{576}{x^2} =1 \\  \\ \Rightarrow x^2=576 \\  \\ \Rightarrow x=\sqrt{576}=24

Now, recall that

y= \frac{288}{x} = \frac{288}{24} =12

Thus, the length of fencing needed is given by

P = x + 2y = 24 + 2(12) = 24 + 24 = 48.

Therefore, 48 feets of fencing is needed to enclose the garden.
8 0
3 years ago
How many centiliters are in 6.02 decaliters?
Aloiza [94]
1 centiliter is .01 of a liter. 

6.02 decaliter is 60.2 liters. 

6.02  decaliter is also 6020 centiliters 

So 6.02 decaliter is 6020 centiliters
6 0
3 years ago
A growth medium is inoculated with 1,000 bacteria, which grow at a rate of 15% each day. What is the population of the culture 6
ddd [48]

Answer:

The population of bacteria after 6 days is 2,313.06

Step-by-step explanation:

Given as :

The initial population of bacteria = i = 1,000 bacteria

The growth rate of bacteria per day = 15%

Let The population of bacteria after 6 days = f

The time period of growth = 6 days

<u>Now, According to question</u>

The population of bacteria after 6 days = initial population × (1+\dfrac{\textrm rate}{100})^{\textrm time}

Or, f = i × (1+\dfrac{\textrm r}{100})^{\textrm t}

Or, f = 1000 × (1+\dfrac{\textrm 15}{100})^{\textrm 6}

Or, f = 1000 × (1.15)^{6}

Or, f = 1000 × 2.31306

∴  f = 2,313.06

So,The population of bacteria after 6 days = f = 2,313.06

Hence,The population of bacteria after 6 days is 2,313.06  Answer

3 0
3 years ago
Question
Kaylis [27]

Answer:

55w+145

Step-by-step explanation:

10w+120+45w+25 = 55w+145

4 0
2 years ago
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