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3 years ago

I need know what 18 divided by 9.63 equals

Mathematics

2 answers:

pshichka [43]3 years ago

6 0

The answer is 1.869 or 1.87

gayaneshka [121]3 years ago

6 0

Do you mean 9.63 divided by 18?

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Ganezh [65]

Answer:

the answer is

B.Plate

i hope this helps ~_~

4 0

2 years ago

Read 2 more answers

Fred has 230 animals at his zoo. Grace at 349 more animals in her zoo than Fred has. how many animals do they have altogether? T

WARRIOR [948]

Step-by-step explanation:

okay so im in 8th grade and i just worked the problem out and i got , 809 ,

first you add 230 + 349 to see how much she has in her farm

she has 579, then you add 579 because she has that many , and he has 230 so you add 579 +230 and tou get 809

work:

230

+349

----------

579

+230

---------

809

hope i helped!!

4 0

3 years ago

F(x) = square root x-3

aleksandrvk [35]

I think the answer is c

7 0

2 years ago

The mean of 10 values is 19. If further 5 values are

Leokris [45]

Answer:

Step-by-step explanation:

Pretend the 10 values in the first sentence are a,b,c,d,e,f,g,h,i,j

Pretend the addition 5 values is k,l,m,n,o

So the mean of all the 15 data is (a+b+c+d+e+f+g+h+i+j+k+l+m+n+o)/15=20

So the sum of all 15 data is a+b+c+d+e+f+g+h+i+j+k+l+m+n+o=300 since 15(20)=300

Now let's look at the first 10: We have their mean so we can write:

(a+b+c+d+e+f+g+h+i+j)/10=19

so a+b+c+d+e+f+g+h+i+j=190 since 10(19)=190

So that means using our first sum equation and our equation sum equation we have

190+k+l+m+n+o=300

k+l+m+n+o=300-190

k+l+m+n+o= 110

So the average of those 5 numbers mentioned in your problem is 110/5=22

3 0

3 years ago

A state end-of-grade exam in American History is a multiple-choice test that has 50 questions with 4 answer choices for each que

Assoli18 [71]

Answer:

Q1) The student has a 0.01% probability of passing the test.

Q2) She has a 99.91% probability of passing in the test.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either he gets it correct, or he gets it wrong. So we solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

For this problem, we have that:

Question 1.

There are 50 questions, so $n = 50$ .

The student is going to guess each question, so he has a $\pi = \frac{1}{4} = 0.25$ probability of getting it right.

He needs to get at least 25 question right.

So we need to find $P(X \geq 25)$ .

Using a binomial probability calculator, with $n = 50$ and $\pi = 0.25$ we get that $P(X \geq 25) = 0.0001$ .

This means that the student has a 0.01% probability of passing the test.

Question 2.

Now, we need to find $P(X \geq 25)$ with $\pi = 0.70$ . So $P(X \geq 25) = 0.9991$

She has a 99.91% probability of passing in the test.

7 0

3 years ago

Read 2 more answers