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2 years ago

Find the value of 17C3 680 12,376 2,380 54

Mathematics

2 answers:

trapecia [35]2 years ago

7 0

Answer:

54 because I don't know I can't explain

SVEN [57.7K]2 years ago

6 0

Answer:

680

Step-by-step explanation:

Using the definition

n $C_{r}$ = $\frac{n!}{r!(n-r)!}$

where n! = n(n - 1)(n - 2)...... × 3 × 2 × 1

17 $C_{3}$

= $\frac{17!}{3!(14)!}$

Cancel the multipliers of 14 × 13 ×...... on the numerator with 14! on denominator.

= $\frac{17(16)(15)}{3(2)(1)}$

= $\frac{4080}{6}$

= 680

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GaryK [48]

Answer:

Equivalent expressions

A) $\frac{60}{-5}$

C) $60\times (-\frac{1}{5})$

Step-by-step explanation:

Given expression :

$\frac{-60}{5}$

Choices given :

A) $\frac{60}{-5}$

B) $60\times \frac{1}{5}$

C) $60\times (-\frac{1}{5})$

D) $-60\times (-\frac{1}{5})$

To find the equivalent expression.

We will first evaluate the given expression.

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Evaluating each choice to select the equivalents.

A) $\frac{60}{-5}$

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⇒ $\frac{60}{5}$

⇒ $12$

C) $60\times (-\frac{1}{5})$

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2 years ago

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yaroslaw [1]

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marysya [2.9K]

Answer:

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Interval Notation:

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Step-by-step explanation:

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frosja888 [35]

Answer:

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