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White raven [17]
3 years ago
9

Melinda has shown that a function, f(x), increases by 4 for every unit in the domain. What does this prove?

Mathematics
2 answers:
Virty [35]3 years ago
8 0

Answer:

Option 1 is correct that is the function f(x) is an arithmetic sequence.

Step-by-step explanation:

We have been given the information that function is increasing by 4 for every unit in the domain.

That means difference between the consecutive terms will be same that is common difference exists

For example:

we have a function f(x)=x

Since, it is increasing by 4 for every unit means function becomes x,x+4,x+4+4

The common difference is 4.

Hence, the function f(x) is an arithmetic sequence.

therefore, option 1 is correct.

lisov135 [29]3 years ago
4 0

By definition, we have to:

An arithmetic sequence is a sequence of numbers that increases or decreases by a constant amount each term.

We can write a formula for the term n of an arithmetic sequence in the form:

an = d * n + c

Where,

n: domain variable

c: initial value

d: constant term.

For this case we have:

an = 4 * n + c

Answer:

The function f (x) is an arithmetic sequence.

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Doug hits a baseball straight towards a 15 ft high fence that is 400 ft from home plate. The ball is hit 2.5ft above the ground
Scorpion4ik [409]

Answer:

125.4\ \text{m/s}

Step-by-step explanation:

u = Initial velocity of baseball

\theta = Angle of hit = 30^{\circ}

x = Displacement in x direction = 400 ft

y = Displacement in y direction = 15 ft

y_0 = Height of hit = 2.5 ft

a_y = g = Acceleration due to gravity = 32.2\ \text{ft/s}^2

t = Time taken

Displacement in x direction

x=u_xt\\\Rightarrow x=u\cos\theta t\\\Rightarrow t=\dfrac{x}{u\cos\theta}\\\Rightarrow t=\dfrac{400}{u\cos30^{\circ}}\\\Rightarrow t=\dfrac{400}{u\dfrac{\sqrt{3}}{2}}\\\Rightarrow t=\dfrac{800}{u\sqrt{3}}

Displacement in y direction

y=y_0+u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow y=y_0+u\sin\theta t+\dfrac{1}{2}a_yt^2\\\Rightarrow 15=2.5+u\sin30^{\circ}(\dfrac{800}{u\sqrt{3}})+\dfrac{1}{2}\times -32.2\times (\dfrac{800}{u\sqrt{3}})^2\\\Rightarrow \dfrac{400}{\sqrt{3}}-\dfrac{10304000}{3u^2}-12.5=0\\\Rightarrow 218.44=\dfrac{10304000}{3u^2}\\\Rightarrow u=\sqrt{\dfrac{10304000}{3\times218.44}}\\\Rightarrow u=125.4\ \text{m/s}

The minimum initial velocity needed for the ball to clear the fence is 125.4\ \text{m/s}

5 0
3 years ago
I dunno how to do this im just hoping people know the answer
9966 [12]

Answer:

its always wrong

Step-by-step explanation:

any variable always has a holder of 1

so 01b doesnt equal 4

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3 years ago
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A

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