Answer:
Step-by-step explanation:
Given the differential equation y''-10y'+29y=0
First, we need to rewrite it as an auxiliary equation as shown:
Let y'' = m²y and y' = my
Substitute the values into the general equation
m²y-10my+29y = 0
Factor out y:
(m²-10m+29)y = 0 [The auxiliary equation]
Solve the auxiliary equation and find the roots of the equation
m²-10m+29 = 0
m = -b±√(b²-4ac)/2a
a = 1, b = -10, c = 29
m = -10±√(10²-4(1)(29))/2(1)
m = -10±√(100-116)/2
m = -10±√-16/2
m = (-10±4i)/2
m = -10/2 + 4i/2
m = -5+2i
Comparing the complex number with a+bi, a = -5 and b = 2
The general solution for complex solution is expressed as:
Substitute the value of a in the equation
Hence the general solution to the differential equation is
Answer:
y=-1/4x-6
Step-by-step explanation:
The problem wants the form y=mx+b where m is the slope and b is the y-intercept.
The y-intercept in this case is -6 (where the line intercepts the y-axis).
We can use points (0,-6) and (4,-7) to calculate the slope. We just divide the difference in y-values by the difference in x-values.
-6-(-7)/0-4=-6+7/-4=1/-4=-1/4
So the equation of the line is y=-1/4x-6
T would equal to 63!
7 • 9= 63
The answer is -2 for the csc and it’s also a rational denominator
Answer:
A. The reference angle should be pi/3, and the sign of the value should be negative.
Step-by-step explanation:
Just took the unit review.